Question

When dragons on planet Pern lay eggs, the eggs are either green or yellow. The biologists have observed over the years that 32% of the eggs are yellow, and the rest green. Next spring the lead scientist has permission to randomly select 59 of the dragon eggs to incubate. Consider all the possible samples of 59 dragon eggs.
What is the usual number of yellow eggs in samples of 59 eggs? (Give answers as SENSIBLE whole numbers.)


minimum usual number of yellow eggs =



maximum usual number of yellow eggs =

Answer 1

Answer and Step-by-step explanation:

The computation is shown below

Given that as per the question

n = 59

p = 0.32

Therefore mean is

$=\mu$

$= np$

$= 59 \times 0.32$

= 18.88

Now the standard deviation i.e $\sigma$

$= \sqrt{np(1-p)}$

$= \sqrt{18.88(1 - 0.32)}$

= 3.58

Now the minimum usual number of yellow eggs is

$= \mu - 2\times \sigma$

$= 18.88-2 \times 3.58$

= 12 yellow eggs

And, the maximum number is

$= \mu + 2\times \sigma$

$= 18.88 + 2 \times 3.58$

= 26 yellow eggs