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Inessa [10]
3 years ago
6

There were twelve times more children than adults at the matinee performance of

Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Answer:

Call the number of children and adults, c and a.

Then we have

c = 12a and

c + a = 455

Substituting we have

12a + a = 455

13a = 455

a = 35 adults

c = 12(35) = 420 kids

Step-by-step explanation:

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16 31 Here is a compound shape made from two rectangles. - 6 cm 4 cm NOT DRAWN 9 cm TO SCALE 12 cm n ek NO ME (a) Calculate the
maks197457 [2]

Answer:

Well perimeter is adding up all the sides since it's a rectangle the first one is just 6 + 6 + 4 + 4 = 20 cm

The second would be 9 + 9 + 12 + 12 = 42 cm if this is not an option or if it is wrong let me know and I will try again

3 0
2 years ago
Helpp me please
Leto [7]

Answer:

  • 9) c, 10) c, 11) a

Step-by-step explanation:

<h3>#9</h3>

Total charge consists of the cost of the  tarpaulin, which is 15x and lay outing cost of Php 150:

  • y = 15x + 150

Correct choice is c.

<h3>#10</h3>

We are interested in the outcome so the brand of PC is not something to concern us.

<u>Excluding the option II, we have one correct choice:</u>

  • c. I, III, and IV only
<h3>#11</h3>

<u>The area based on given dimensions is:</u>

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<u>Correct choice is:</u>

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8 0
3 years ago
What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ?
Nonamiya [84]
<span>Perpendicular lines' slopes are reciprocals of one another. So we know the perpendicular line will have a slope of 1/2. Then we can use our points to find the rest. 8=1/2(1)+b 8=0.5+b 7.5=b y=2x+b</span>
7 0
3 years ago
Read 2 more answers
How can I solve 2t+4w=6 + 4t +6w= 15 using elimination?
xeze [42]
I hope this helps you



-2/2t+4w=6


-4t-8w= -12


4t+6w=15


-2w=3


w= -3/2


2t-4.3/2=6


2t=12


t=6
3 0
3 years ago
HELP ME PLEASE WILL PICK BRAINLYEST
Ronch [10]
Here's one way to do it.

AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence

Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
3 0
3 years ago
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