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HACTEHA [7]
3 years ago
5

What element is often found on pie charts

Mathematics
2 answers:
pogonyaev3 years ago
8 0
A common element or description on a pie chart is a percentage. The reason is that percentages are given as a part out of a total (100%).  Pie charts are used to see how individual parts compare to the whole, so percents are often times used to show this.
IRISSAK [1]3 years ago
4 0

Answer: Pie charts typically have 3 elements: labels, legend and title. Of course percentages as well since one full pie is equal to 100%.

Step-by-step explanation:

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The complementary angle of 45
Licemer1 [7]

Answer:

45°

Step-by-step explanation:

Complementary angles sum to 90°, thus

90° - 45° = 45° ← is the complement of 45°

4 0
4 years ago
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Troyanec [42]

Answer:

5.5 pints is the answer to this

5 0
3 years ago
Read 2 more answers
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
3 years ago
How to solve: a parade traveled 4 miles in 2 hours. how far did tge parade travel per minute?
jek_recluse [69]

There's a really easy way to convert any units to other units.

Right now, we have the fraction  (4 miles) / (2 hours).

We want to find a fraction that's exactly equal to that one,
but has the units of  (miles/minute)  or maybe  (feet/minute).

Just take the original fraction, and multiply it by some other
fractions.

Each fraction you multiply it by must have the value of ' 1 ' so
you don't change the value of the original fraction.  But it can
have different units, that cancel with other units to eventually
give you the units you want.

      (4 miles / 2 hours) times (1 hour / 60 minutes)

The second fraction is equal to ' 1 ', because the top and the bottom
have the same value ...  1 hour is the same thing as  60 minutes.

Multiply the fractions:  (4 miles x 1 hour) / (2 hour x 60 minutes)

Now you can cancel 'hour' from the top and the bottom, and you have

             (4 miles x 1) / (2 x 60 minutes)

               = (4 miles) / (120 minutes) 

               =          (4 / 120) mile/minute = 0.0333... mile / minute .

Let's do it again, go a little farther, and get an answer that
might mean more and feel more like an answer. 

   (4 miles) / (2 hours) x (5280 feet / mile) x (1 hour / 60 minutes)

The 2nd and 3rd fractions both have the value of ' 1 ', because
the top is equal to the bottom. 

Multiply all three fractions: 

     (4 miles x 5280 feet x 1 hour) / (2 hours x 1 mile x 60 minutes)

You can cancel both 'mile' and 'hour' out of the top and bottom,
and look what you have left:

     (4 x 5280 feet x 1) / (2 x 1 x 60 minutes)

  =  (4 x 5280) / (2 x 60)  feet / minutes

  =  (21,120 / 120)  feet/minute   =    176 feet per minute
  
3 0
3 years ago
Read 2 more answers
What is the simplified form of the quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the qua
scoundrel [369]
\frac{x + 4}{7} -\frac{x + 3}{x + 5} =\frac{(x + 4)(x + 5)}{7(x + 5)} -\frac{7(x + 3)}{7(x + 5)} =\frac{x(x + 5) + 4(x + 5)}{7(x) + 7(5)} - \frac{7(x) + 7(3)}{7(x) + 7(5)} =\frac{x(x) + x(5) + 4(x) + 4(5)}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{x^{2} + 5x + 4x + 20}{7x + 35} -\frac{7x + 21}{7x + 35} =\frac{x^{2} + 9x + 20}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{(x^{2} + 9x + 20) - (7x + 21)}{7x + 35} =\frac{x^{2} + (9x - 7x) + (20 - 21)}{7x + 35} =\frac{x^{2} + 2x -1}{7x + 35}
3 0
3 years ago
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