At southern states university ssu there are 719 students taking finite mathematics or statistics. 328 are taking finite mathemat
2 answers:
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This can be solved by factoring.
First, set the expression equal to zero.
Then, find two the factors of
whose sum is 
.
Split into these two factors.
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree
has exactly complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done. Your answers are -2 and 1/3. There are two real roots.
First, set the expression equal to zero.
Then, find two the factors of
Split
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree
The function is an exponential with base greater than 1. So, its range is
, with 0 being the horizontal asymptote as
.
If you multiply the function by , the range remains the same.
If you reflect it over the x-axis, you're changing the sign of the function. So, the new range is