Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
3
1
2
Step-by-step explanation:
Math simplification
Answer:

Step-by-step explanation:
Use cosine:


We have:

Substitute:

<em>cross multiply</em>
<em>divide both sides by 9063</em>

3^(-4) means "one over 3^4"
1/(3^4)
That's equal to
1/81
and
(1/3)^4
This is also equal to 3^2/3^6.
So four of those are correct.
d = r · t ⇒ t = d/r
going
t = 54/(r + 4)
coming
t = 30/(r - 4)
54/(r + 4) = 30/(r - 4) times are equal
54(r - 4) = 30(r + 4) product means/extremes
54r - 216 = 30r + 120 distribute
24r - 216 = 120 subtract 30r from both sides
24r = 336 add 216 to both sides
r = 14 divide both sides by 24
Alfonso bikes at 24 mph.