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2 years ago

8

What kind of transformation converts the graph of f(x) = 5x - 2 into the graph of g(x) = x -2

1 answer:

malfutka [58]2 years ago

5 0

Answer:

Vertical compression

Step-by-step explanation:

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

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Sonbull [250]

Answer:

Solution given:

lowest =0

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2 years ago

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nataly862011 [7]

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2 years ago

Alex has 4 less than twice the number baseball cards as leo. ginny has 12 more than three times the number of baseball cards Leo

marin [14]

Alex has 128 baseball cards, Leo has 66 cards, and ginny has 210.

6 0

2 years ago

Solve for a and x in ax^2=48<br>

Gelneren [198K]

Answer:

$ax^2 = 48\\a = \frac{48}{x^2}$

$ax^2 = 48\\x^2 = \frac{48}{a} \\x = \frac{\sqrt{48} }{\sqrt{a} } \\x = \frac{4\sqrt{3} }{\sqrt{a}} \\x = \frac{4\sqrt{3a} }{a}$

6 0

2 years ago

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

4 0

2 years ago