Answer:
New cells are naive to the infectious cells who attack it or they are not well prepared to deal with the different scenarios. But, the cells who are attacked before has the set or sequence of the viral or bacterial genome strand been identified by them, which leads to more safety or protection from these foreign bodies.
Explanation:
- Mechanism To attack a host cell:
The viruses and other infectious material enters and attacks the host cell, by breaching its membrane wall and installing or leaving a gene of its own inside the cell. Which then combines with the genome of the cell and it goes through the process of replication, translation etc,along with the host cell machinery. Which then spreads the specific gene strand more in the environment
- <u>Camouflage obtained by the infectious cell to hide it self:</u>
After the genome enters the host cell at first it does not recognizes the strands or foreign cells, as they cover there body with a camouflage sort of membrane and they look more like the body cells.
- <u>Reactions by the host cell and as a whole the body:</u>
The organisms detects the genome of the infections cells or strand, as they store the data about it in its server or database. As if the next time they were under attack then precautions will be there by the host cell to deal with it.
As for the cell who are never attacked before will be less safe to deal with these foreign bodies.
The answer is: " 32,768 " .
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Explanation:
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→ 2ⁿ = ? ; {that is: "2" , raised to the "n th" power, equals {<u>what value</u>} ?
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→ Note that "n" is the haploid number, which is:
"15" (value given within this very question).
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→ So we plug in "15" for "n" ; to obtain the "final value" —
which is the answer.
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→ As such: " 2¹⁵ = 32,768 " . (using scientific calculator online).
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→ The answer is: " 32,768 " .
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Answer:
D. There isn't enough information to determine which is the coding strand
Explanation:
In this protein, it would be necessary to observe a start codon (ATG) and one-stop codon (either TAA, TAG, or TGA) which should be separated by six (6) intern codons. It is not observable this nucleotide sequence in any of both DNA strands.
