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Y_Kistochka [10]
2 years ago
15

Problem Page

Mathematics
1 answer:
Montano1993 [528]2 years ago
6 0

Answer:

425 mm


Step-by-step explanation:

The ratio of compound A to compound B is 5 is to 6.

So, we can say that the total ratio is of 11 parts (5+6=11).

<em><u>If the chemist wants a total of 935 mm of the drug, then each of the 11 parts are worth:</u></em>

\frac{935}{11}=85


<em>From the ratio, we know that Compound A is 5 parts. So:</em>

85*5=425

425 mm of Compound A is needed.

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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

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3 years ago
X=2t/t^2 +1 and y=2t/t^2 +1 <br>Find dy/dx​
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Answer:

dy/dx=1

Hope this helps! Please vote brainliest! :)

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2 years ago
Please help me :( A standard six-sided die is rolled. What is the probability that it is not a 4?
zmey [24]

Answer:

The answer is 5/6, or .833, 3 repeated.

Step-by-step explanation:

The 4 is only one side of the die, or 1/6 if the surface of the die. So the other part that is left is the other 5/6 of the surface.

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In a function, the range is the y value or axis. Most points on this graph have a y value of zero, but one has a value of 1.

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3 years ago
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A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a
tatuchka [14]

Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

n=15 sample size  

\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

The statistic for this case would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

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