Question

A kid moving 3.18 m/s jumps on a slip and slide(Uk=0.0751). How far has he slid when his velocity is reduced to 2.00 m/s?

Answer 1

F=ma (Newton's second law of motion).

Then,
a = F/m = Uk*mg/m = Uk*g = 0.0751*9.81 = 0.737 m/s^2 (should be negative since a deceleration is expected).

v = Sqrt (u^2-2ad), Where v = final velocity, u=initial velocity, a = acceleration, d = distance moved.

Therefore,

v^2-u^2 = -2ad => d = (v^2-u^2)/-2a = (2^2-3.18^2)/-2*0.737 = 4.15 m