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Leni [432]
3 years ago
15

If a 5.0 kg box is pulled simultaneously by a 10.0 N force and a 5.0 N force, then its acceleration must be?

Physics
1 answer:
kicyunya [14]3 years ago
6 0

For this case we have that by definition:

F = ma

Where,

  • <em>m: mass of the object </em>
  • <em>a: acceleration of the object </em>
  • <em>F: summation of forces </em>

We have then:

F = 10 + 5\\F = 15 N

Then, by clearing the acceleration we have:

a = \frac {F} {m}

Substituting values we have:

a = \frac {15} {5}\\a = 3 \frac {m} {s ^ 2}

Answer:

The acceleration of the box is equal to:

a = 3 \frac {m} {s ^ 2}

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3 years ago
A 7.8 µF capacitor is charged by a 9.00 V battery through a resistance R. The capacitor reaches a potential difference of 4.20 V
Vaselesa [24]

Answer:

655128 ohm

Explanation:

C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F  

V₀ = Voltage of the battery = 9 Volts  

V = Potential difference across the battery after time "t" = 4.20 Volts  

t = time interval = 3.21 sec  

T = Time constant

R = resistance  

Potential difference across the battery after time "t" is given as  

V = V_{o} (1-e^{\frac{-t}{T}})

4.20 = 9 (1-e^{\frac{-3.21}{T}})

T = 5.11 sec  

Time constant is given as  

T = RC  

5.11 = (7.8 x 10⁻⁶) R  

R = 655128 ohm

3 0
3 years ago
I can’t figure this out!!! Answer what you can , please.
tigry1 [53]

a/b. The ball has velocity vector at time t

\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)

where v_0=16\dfrac{\rm m}{\rm s} is the ball's initial speed and g=9.8\dfrac{\rm m}{\mathrm s^2}.

c. At its highest point, the ball has 0 vertical speed. This occurs when

v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s

d. Recall that

{v_y}^2-{v_{0y}}^2=-2g\Delta y

so that at its highest point,

0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m

e. This is just twice the time it takes for the ball to reach its maximum height, t=2.9\,\mathrm s.

f. The ball's horizontal position after time t is

v_0\cos63^\circ\,t

so that after the time found in part (f), the ball has traveled

v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m

4 0
4 years ago
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