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hammer [34]
3 years ago
9

Researchers want to see if college students are more committed to their fraternity after going through a hazardous hazing ritual

. What is the dependent variable?
Physics
1 answer:
Mila [183]3 years ago
8 0

Answer:

College student's commitment

Explanation:

The dependent variable is  the college students since it  is the variable we are going to measure as a result of the independent variable which is  the hazardous hazing ritual or non-hazardous hazing ritual.

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Answer:

Distance travelled is 7 meters and the displacement is 3 meters

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2 years ago
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Describe three physical changes that occur in nature?
Alex Ar [27]

Answer: Physical changes in nature could then be erosion in a mountain, the melting of snow, and a river freezing over from the cold. Since none of these changes affect the chemical composition of the mountain, the snow, or the river, they are physical changes.

Explanation:

8 0
3 years ago
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You want to produce three 2.00-mm-diametercylindrical wires, each with a resistance of 1.00 Ω at room temperature. One wire is g
Vlada [557]

Answer:

(a) L =  128.75 m

(b) L =  182.56 m

(c) L =  114.28 m

(d) Mass of Gold = 7.68 kg = 7680 gram

(e) Cost of Gold Wire = $ 307040

Explanation:

The resistance of the wire is given as:

R = ρL/A

where,

R = Resistance

ρ = resistivity

L = Length

A = cross-sectional area

(a)

For Gold Wire:

ρ = 2.44 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (2.44 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(2.44 x 10⁻⁸ Ω.m)

<u>L =  128.75 m</u>

<u></u>

(b)

For Copper Wire:

ρ = 1.72 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (1.72 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(1.72 x 10⁻⁸ Ω.m)

<u>L =  182.56 m</u>

<u></u>

(c)

For Aluminum Wire:

ρ = 2.75 x 10⁻⁸ Ω.m

A = πd²/4 = π(2 x 10⁻³ m)²/4 = 3.14 x 10⁻⁶ m²

R = 1 Ω

Therefore,

1 Ω = (2.75 x 10⁻⁸ Ω.m)L/(3.14 x 10⁻⁶ m²)

L = (1 Ω)(3.14 x 10⁻⁶ m²)/(2.75 x 10⁻⁸ Ω.m)

<u>L =  114.28 m</u>

<u></u>

(d)

Density = Mass/Volume

Mass = (Density)(Volume)

Volume of Gold = AL = (3.14 x 10⁻⁶ m²)(128.75 m) = 4.04 x 10⁻⁴ m³

Therefore,

Mass of Gold = (1.9 x 10⁴ kg/m³)(4.04 x 10⁻⁴ m³)

<u>Mass of Gold = 7.68 kg = 7680 gram</u>

<u></u>

(e)

Cost of Gold Wire = (Unit Price of Gold)(Mass of Gold)

Cost of Gold Wire = ($ 40/gram)(7680 grams)

<u>Cost of Gold Wire = $ 307040</u>

7 0
3 years ago
Think Critically Suppose your teacher gave you a slide of an unknown cell. How would you tell whether the cell was from an anima
topjm [15]

Answer:

You will be able to tell whether the unknown cell is from an animal or from a plant through the knowledge of difference between plants and animal cells.

Explanation:

A cell can be defined as the simplest bit of living matter which exhibits a variety of shapes and sizes and that can exist independently.

When a slide of an unknown cell is studied under a microscope, different cell structures would be observed which would be used to conclude if the cell on the slide is a plant or animal cell.

The following features are observed in a plant cell:

--> cellulose cell wall is present

--> Chloroplast is present

--> A large central vacuole is present

--> Centriole is absent

The following features are observed in animal cell:

--> Cellulose cell wall is absent

--> Chloroplast is absent

--> Small vacuoles is present

--> Centriole is present

The difference between a plant and an animal cell can be seen from the features above and a clear knowledge of this will help the student tell whether the unknown cell is from an animal or from a plant.

4 0
2 years ago
If a car is accelerating downhill under a net force 3674 N , what additional force would cause the car to have a constant veloci
Semenov [28]

Answer:

For the car to move with constant velocity the additional force required is  F__{dg} }=  -3674 \  N

Explanation:

From the question we are told that

  The net force of the car is  F_{net} = 3674 \  N

Generally the total  force acting on the  car is the net force plus the force due to gravity acting in direction of the car (Let denote it as F__{dg})

So the total force acting on the car is mathematically represented as

        F_{net} + F__{dg}} = F

Here this F representing the total force can be mathematically represented as

      F =  ma

Now for constant velocity to be attained, the acceleration of the car will be zero  

So  at constant velocity

       F =  m * 0

=>    F =   0 \  N

So  

     F_{net} + F__{dg}} = 0

=>   F__{dg} }=  -F_{net}

=>   F__{dg} }=  -3674 \  N

6 0
2 years ago
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