Answer:
10
Explanation:
The distance between two points of coordinates (x1, y1) and (x2, y2) can be calculated as:
![\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
So, the distance between (-2, 5) and (8, 5) is equal to:
![\begin{gathered} \sqrt[]{(8-(-2))^2+(5-5)^2} \\ \sqrt[]{(8+2)^2+(0_{})^2} \\ \sqrt[]{(10)^2+0} \\ \sqrt[]{100} \\ 10 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7B%288-%28-2%29%29%5E2%2B%285-5%29%5E2%7D%20%5C%5C%20%5Csqrt%5B%5D%7B%288%2B2%29%5E2%2B%280_%7B%7D%29%5E2%7D%20%5C%5C%20%5Csqrt%5B%5D%7B%2810%29%5E2%2B0%7D%20%5C%5C%20%5Csqrt%5B%5D%7B100%7D%20%5C%5C%2010%20%5Cend%7Bgathered%7D)
Then, the distance between (-2, 5) and (8, 5) is 10.
Answer:
( C ) ΔMLN ≅ΔTSR
Step-by-step explanation:
Okay I got you!
So if the triangle <u>str</u> was flipped and rotated the other way then you will see that they are similar. They are asking what other "pairs" could you do to make it equivalent. Since M = T then you got your first pair. Next you go to N and when you look at the shape you'll see it will be S. N=S. And the last one would be L=R. I hope I was helpful enough! uwu Try to draw them out it will be helpful!!
Answer:
Step-by-step explanation:
The answer is A for both
Answer:
Approximately
.
Step-by-step explanation:
The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.
Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height:
.
Apply the power rule to find the first derivative of this
with respect to time
.
By the power rule:
- the first derivative of
(same as - the first derivative of
(same as
to the second power) with respect to
Therefore:
.
In other words, the (vertical) velocity of this arrow at time
would be
meters per second.
Evaluate this expression for
to find the (vertical) velocity of this arrow at that moment:
.

= (1/2) (17.2) (7.1) sin (21.67)
= 22.5470 square meters