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tamaranim1 [39]
4 years ago
15

PLEASE HELP WILL MARK BRAINLIEST!!!! BECT TO LAST QUESTION

Mathematics
1 answer:
Stells [14]4 years ago
8 0
Joint Frequency because of the fact that it "joins" one number from the column(up and down) and one from the row(side-by-side), hence the two-way table.
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Not only would I like the value of x, but also I wonder how I’d go about solving this problem?
notsponge [240]

Answer:

x = 58

Step-by-step explanation:

This question can be solved by using the exterior angle property, which states that the exterior angle of a triangle = the sum of the two opposite interior angles.

62 lies on a line, so the exterior angle is 180 - 62, or 118 degrees.

Using the EAP, we can conclude the following:

(x + 2) + (x) = 118

2x + 2 = 118

2x = 116

x = 58

Hope this helps

4 0
2 years ago
Read 2 more answers
Trigonometry
Fiesta28 [93]

Answer:

-7/18

Step-by-step explanation:

cos(2x) = 1 - 2sin²x

cos(2x) = 1 - 2(5/6)²

= 1 - 2(25/36)

= 1 - 25/18

= -7/18

5 0
3 years ago
Read 2 more answers
What is the slope of the line described by the equation 4x + 6y = 12?
Eddi Din [679]
-2/3 is the correct answer
6 0
3 years ago
Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
4 years ago
Which line has a slope of 1/2?
madam [21]

Answer: line c because 1 is rise and 2 is run and in line c also it is rising by 1 and rnning by 2 so line c is answer


Step-by-step explanation:


4 0
4 years ago
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