Can somebody solve this advanced algebra problem ?
1 answer:
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Answer:
Choice D: Perimeter = 5 + +
units
Step-by-step explanation:
point B(9, 2) , point C(4, 5), point A (1,1)
Perimeter = D( A, C) + D (A, B) + D (B, C)
where D (A, C) = distance between A and C
so...
D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5 from a 3-4-5 right triangle.
D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)
D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)
Perimeter = 5 + root(65) + root(34)
Perimeter = 5 + +
units