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Pavel [41]
3 years ago
8

Gina is getting a new bathroom mirror. The rectangular mirror measures 666 meters by 888 meters. What is the amount of space the

mirror will cover on the wall?
Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0
<h2>Answer:</h2><h2>The amount of space the mirror will cover on the wall is 48m²</h2>

Step-by-step explanation:

If Gina is getting a new bathroom mirror which is rectangular in nature and measures 6 metres by 8 metres, the amount of space the mirror will cover on the wall will be the area of the rectangular mirror.

Since the mirror is rectangular in nature, we will use the formula for finding the area of a rectangle as shown;

Area of a rectangle = Length * Breadth

Area of the rectangular mirror = 6 * 8

Area of the rectangular mirror = 48m²

The amount of space the mirror will cover on the wall is 48m²

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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)= 7,u'(0)=-5,v(0)= -1, v'(0)= -4.
andriy [413]

This question is incomplete, the complete question is;

Suppose u and v are functions of x that are differentiable at x=0

and that { u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

Find the values of the following derivatives at x = 0.

a) \frac{d}{dx}( uv )

b)  \frac{d}{dx}( \frac{u}{v} )

c)  \frac{d}{dx}( \frac{v}{u} )

Answer:

a) \frac{d}{dx}( uv ) = -23  

b) \frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

Step-by-step explanation:

Given that;

{ u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

a)

\frac{d}{dx}( uv )

we differentiate

\frac{d}{dx}( uv )  = uv' + vu'

at x = (0), we substitute our values

\frac{d}{dx}( uv ) = ( 7 × -4 ) + ( -1 × -5)

\frac{d}{dx}( uv )  = -28 + 5

\frac{d}{dx}( uv ) = -23  

b)

\frac{d}{dx}( \frac{u}{v} )

we differentiate

\frac{d}{dx}( \frac{u}{v} ) = ( vu' - uv' ) / v²

at x=0, we substitute our values

\frac{d}{dx}( \frac{u}{v} ) = ( (-1 × -5) - (7 × -4 ) ) / (-1)²

\frac{d}{dx}( \frac{u}{v} ) = (( 5 - ( -28 )) / 1

\frac{d}{dx}( \frac{u}{v} )  = 33 / 1

\frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} )

we differentiate

\frac{d}{dx}( \frac{v}{u} )  = ( uv' - vu' ) / u²

at x=0, we substitute our values

\frac{d}{dx}( \frac{v}{u} )  = ( (7 × -4) - (-1 × -4) ) / (7)²

\frac{d}{dx}( \frac{v}{u} ) = ( -28 - ( 4 ) ) / 49

\frac{d}{dx}( \frac{v}{u} )  = ( -28 - 4 ) /49

\frac{d}{dx}( \frac{v}{u} )  = -32 / 49

\frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

6 0
3 years ago
PLEASE HURRY Find the measures of the numbered angle
Arte-miy333 [17]

Answer:

  90°

Step-by-step explanation:

The sum of the arcs around the circle is ...

  2x +4x +4x +2x = 360°

  x = 360°/12 = 30°

The numbered angle is the average of the measures of the intercepted arcs, so is ...

  (4x +2x)/2 = 3x = 3(30°) = 90°

The numbered angle is 90°.

8 0
3 years ago
Please help.
grandymaker [24]

Answer:

6T + p

6T + p = 27

T = 4 ; p = 4

Step-by-step explanation:

Given the following :

Points awarded for touchdown = 6 and then try for a point 'p' after touchdown

Hence, number of points scored on

touchdowns T and points after touchdowns p by one team in a game.

6points * number of touch downs (T) + point 'p' after touchdown

= 6T + p

B) If a team wins a football game 27-0,

Possible number of touch downs and points after touchdown :

Then 6T + p = 27

27 / 6 = 4 remainder 3

Hence, possible number of touch downs = 4

Number of points p = 27 - (6*4) = 27 - 24 = 3

C.) if winning = 21-7

Team A = 21

Hence, T = 21/6 = 3 remainder 3

T = 3 ; p = 3

Team B = 7

T = 7/6 = 1 remainder 3

T = 1 ; p = 1

Hence,

Total for both teams :

T = (1 + 3) = 4

p = (3 + 1) = 4

7 0
3 years ago
PLEASE HURRY!!!
ella [17]

Answer: The answer to this question is

A.n

Step-by-step explanation:

5 0
3 years ago
What is the place value relationship of the 9's in 299
eimsori [14]
Ones and tens thats the anwers

8 0
4 years ago
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