Let us first define Hypotenuse Leg (HL) congruence theorem:
<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>
Given ACB and DFE are right triangles.
To prove ΔACB ≅ ΔDFE:
In ΔACB and ΔDFE,
AC ≅ DF (one side)
∠ACB ≅ ∠DFE (right angles)
AB ≅ DE (hypotenuse)
∴ ΔACB ≅ ΔDFE by HL theorem.
Answer:
Slope-int form: y = 3x+5
Standard form: y - 3x = 5.
Step-by-step explanation:
(reminder: slope-intercept form is expressed as y=mx+b, and standard form is expressed as ax+bx=c.)
Since the slope is 3, the coefficient of x is also 3, which makes the equation y=3x.
But the y coordinate of the equation at x = -2 is -6, so we need to add 5 to the end of the equation, leaving you with:
y=3x+5.
To convert it to standard form, subtract 3x from both sides:
y - 3x = 5.
I hope this helped you.
Answer:
p+q = 38/15
Step-by-step explanation:
2/3+p = 1. p = 1 - 2/3
4/5 + q = 3. q = 3 - 4/5
p + q = 1 - 2/3 + 3 - 4/5
-2/3 - 4/5 (common denominator = 15)
4 - 10/15 - 12/15 = 4 - 22/15
4 - 22/15 = (4*15 - 22)/15
= 38/15
i would say h or j, but I’m more towards j :)))
