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2 years ago

How do I solve for x? 10x+6=8-2(x+6)

Mathematics

1 answer:

Neporo4naja [7]2 years ago

6 0

1. 10x+6=8-2(x+6)

2. 10x+6=6(x+6)

(distribute the 6)

3. 10x+6=6x+36

(Move the 6x to the other side by subtracting)

4. 4x+6=36

(Move the 6 to the other side by subtracting)

5. 4x=30

(divide)

x=7.5

Hope this helped! :)

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Step-by-step explanation:

This ratio can also be written like this:

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bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$