Question

Please answer all questions and you will get brainliest:

Answer 1

Question 1

We want to find real values of c, for which

${x}^{2} - 8x + c$

is the square of a binomial.

If the above quadratic equation is the square of a binomial, then its discriminant is zero.

This implies that:

$D = {b}^{2} - 4ac = 0$

where a=1, and b=-8

We substitute the values into the formula:

${( - 8)}^{2} - 4(1)(c) = 0$

$64- 4c= 0 \\ 4c = 64 \\ c = 16$

Question 2

We want to find the value of s for which

${x}^{2} + sx + 144$

is the square of a binomial.

In this case too the discriminant must be zero.

D=b² -4ac=0

We put a=1,b=s, and c=144 to obtain:

${s}^{2} - 4(1)(144) = 0$

${s}^{2} - 576 = 0$

${s}^{2} = 576$

$s = \pm \sqrt{576}$

$s = \pm24$

Question 3

We want to find the value of c, for which

$4 {x}^{2} + 14x + c = 0$

Again we have:

${b}^{2} - 4ac = 0$

We put a=4 and b=14

${14}^{2} - 4(4)(c) = 0$

$196 - 16c = 0$

$16c = 196$

$c = \frac{49}{4}$