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2 years ago

5

If the ratio of markers to erasers is 5:2. How many

1 answer:

Leviafan [203]2 years ago

5 0

Answer:

80 markers

Step-by-step explanation:

Set it up as an equation.

markers/erasers 5/2=x/32

Cross multiply to get 160=2x

x=80

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If a line slope of -1/2 contains the point (2,3), then it must also contain which of the following points?

tiny-mole [99]

Before the fraction: -1/2, i have a negative sign
use y=mx+b
3=-1/2(2)+b
3+1=-1+b+1
4=b
check your work
0=-1/2x+4
0+4=-1/2x
(4)÷(-1/2)=(-1/2x)÷(-1/2)
-2=x
another pair is (-2,0) use this to figure out the other points, and/or the points you have in the multiple choice.

5 0

3 years ago

Simplify the expression:<br> 3j–1+4

RUDIKE [14]

Answer:

3j/3—5/3

J=5/3

hope helps

5 0

2 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

<em>Area of polygon D = 10 square units</em>

Step-by-step explanation:

<u>Given:</u>

Polygon <em>C </em>has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

<u></u>

<u>To find:</u>

The area of polygon D = ?

<u>Solution:</u>

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides <em>6, 8 and 10 units.</em>

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = <em>10 sq units</em>

4 0

2 years ago

Find the Antilog of 547.840

bija089 [108]

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

${ \boxed{ \bf{antilog \: of \: x = \frac{x}{ log} = {10}^{x} }}}$

Therefore:

${ \sf{anti(547.840) = {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}$

3 0

3 years ago

What is the volume of the right rectangular prism with a length of 18 inches, a width of 4 inches, and a height of 10 inches? 32

egoroff_w [7]

Answer:

720in

Step-by-step explanation:

V=LWH

V=(18)(4)(10)

7 0

2 years ago

Read 2 more answers