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qaws [65]
3 years ago
7

Classify the given types of matter as either baryonic (ordinary matter that contains protons and neutrons) or as nonbaryonic ("e

xtraordinary" matter that consists of more exotic subatomic particles)
(Select B - Baryonic, N - Nonbaryonic. If the first is B and the rest N, enter
BNNNNN).

a. matter in our bodies
b. dark matter consisting of weakly interacting subatomic particles
c. dark matter consisting of Jupiter-sized planets in galactic halos
d. matter in brown dwarfs
e. matter that probably makes up the majority of dark matter in the universe
Physics
1 answer:
ikadub [295]3 years ago
6 0

Answer:

a) B

b) N

c) B

d) B

e) N

Explanation:

a) The matter in our bodies is the regular matter, basically, we are made of carbon molecules and water. So it involves baryonic matter.

b) In this case, the weakly interacting subatomic particles know as (WIMPs), is the primary candidate for dark matter and this kind of particle has not yet been discovered. We are talking about the nonbaryonic matter.

c) Planets as a Jupiter are made of baryonic matter, in the specific case of Jupiter, it is approximately 75% hydrogen and 24% helium by mass and they are baryonic matter.

d) By definition, brown dwarfs are objects which have a size between a giant gaseous planet like Jupiter and a smaller star, so using the definitions above they are made of baryonic matter.

e) The majority of dark matter is made of non-baryonic matter.

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4 years ago
A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo
blondinia [14]

Answer:

His pitching speed is 38 m/s.

Explanation:

Hi there!

Please see the attached figure for a better understanding of the problem.

The position of the ball at any time t is given by the following vector:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector of the ball at time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

Let's place the origin of the frame of reference at the throwing point so that x0  and y0 = 0.

When the ball reaches the ground, its position vector will be r1 (see figure). Using the equation of the vertical component of the position vector, we can find the time at which the ball reaches the ground. At that time, the horizontal component of the position is 30 m and the vertical component is -3.0 m (see figure):

y = y0 + 1/2 · g · t²  (y0 = 0)

y = 1/2 · g · t²

-3.0 m = 1/2 · (-9.8 m/s²) · t²

-3.0 m / -4.9 m/s² = t²

t = 0.78 s

Now, knowing that at this time x = 30 m, we can find v0:

x = x0 + v0 · t  (x0 = 0)

x = v0 · t

30 m = v0 · 0.78 s

v0 = 30 m / 0.78 s

v0 = 38 m/s

His pitching speed is 38 m/s.

3 0
4 years ago
In an experiment, a rectangular block with height h is allowed to float in two separate liquids. In the first liquid, which is w
Amiraneli [1.4K]

Answer:

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Explanation:

From archimede's principle we know that the force that a liquid exerts on a object equals to the weight of the liquid that the object displaces.

Let us assume that the volume of the object is 'V'

Thus for the liquid in which the block is completely submerged

The buoyant force should be equal to weight of liquid

Mathematically

F_{buoyant}=Weight\\\\\rho _{1}\times V\times g=m\times g\\\\\therefore \rho _{1}=\frac{m}{V}...............(i)

Thus for the liquid in which the block is 1/7 submerged

The buoyant force should be equal to weight of liquid

Mathematically

F'_{buoyant}=Weight\\\\\rho _{2}\times \frac{V}{7}\times g=m\times g\\\\\therefore \rho _{2}=\frac{7m}{V}.................(ii)

Comparing equation 'i' and 'ii' we see that

\rho_{2}=7\times \rho _{1}

Since the first liquid is water thus \rho _{1}=1gm/cm^3

Thus the relative density of the second liquid is 7.

6 0
3 years ago
Read 2 more answers
When a 58g tennis ball is served, it accelerates from rest to a constant speed of 36 m/s. The impact with the racket gives the b
inysia [295]
We first calculate the acceleration on the ball using:
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a = (36)²/(2 x  0.35)
a = 1850 m/s²
F = ma
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= 107.3 Newtons
5 0
3 years ago
Which two properties of light relate to the amount of energy carried by the light? A. speed and amplitude
vivado [14]
C. color and wavelength
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3 years ago
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