Answer:
Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.
If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.
If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.
Answer:
Velocity = 94.85m/s
Explanation:
<u>Given the following data ;</u>
Height = 1200m
Vertical distance = 1050m
To find the time, we would use the second equation of motion;
Substituting into the equation, we have;
t = 11.07 secs
To find the velocity;
Mathematically, velocity is given by the equation;
Substituting into the above equation;
Velocity = 94.85m/s
Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.
B. carbon + oxygen -- carbon dioxide
Explanation:
The best equation that describes a reaction where carbon combines by burning in the presence of oxygen to produce carbon dioxide is:
carbon + oxygen -- carbon dioxide
Every chemical reaction is made up of reactants and products
Reactants are the species on the left hand side of an equation, the products are those on the right hand side.
The reactants combines chemically to give produces.
The kind of reaction depicted above is a synthesis or combination reaction where two species combines to gives a product or more;
C + O₂ → CO₂
learn more:
Chemical reaction brainly.com/question/3953793
#learnwithBrainly
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Answer:
F = 9.81 [N]
Explanation:
To solve this problem we must use Newton's third le which tells us that the sum of forces on a body that remains static must be equal to one resulting from these forces in the opposite direction.
Let's perform a summation of forces on the vertical axis-y to determine the normal force N.
∑F = 0 (axis-y)
where:
m = mass = 4 [kg]
g = gravity acceleration = 9.81 [m/s²]
![N - (4*9.81)=0\\N = 39.24 [N]](https://tex.z-dn.net/?f=N%20-%20%284%2A9.81%29%3D0%5C%5CN%20%3D%2039.24%20%5BN%5D)
Now we know that the frictional force can be calculated using the following equation.
f = μ*N
where:
f = friction force [N]
μ = friction coefficient = 0.25
N = normal force = 39.24 [N]
Now replacing:
![f = 0.25*39.24\\f = 9.81[N]](https://tex.z-dn.net/?f=f%20%3D%200.25%2A39.24%5C%5Cf%20%3D%209.81%5BN%5D)
Then we perform a sum of forces on the X-axis equal to zero. This sum of forces allows us to determine the minimum force to be able to move the object in a horizontal direction.
∑F = 0 (axis-x)
![F-f=0\\F-9.81=0\\F= 9.81[N]](https://tex.z-dn.net/?f=F-f%3D0%5C%5CF-9.81%3D0%5C%5CF%3D%209.81%5BN%5D)
If the coefficient was smaller, a smaller force (F) would be needed to start the movement, this can be easily seen by replacing the value of 0.25, by smaller values, such as 0.1 or 0.05.
If the coefficient were larger, a larger force would be needed.
