Answer:
probability that his sample will contain at least one damaged apple (P) = 0.7215
Step-by-step explanation:
Given:
Probability of damaged apples (p) = 12% = 0.12
number of samples (n) = 10
Consider,
x- number of apples damaged.
Using Binomial distribution formula:
P(x) = 
To find the probability that his sample will contain at least one damaged apple:
P(x≥1) = 1 - P(x<1)
= 1 - P(x=0)
= 1 - 
P(x≥1) = 0.7215
Answer:
Y=√2
Step-by-step explanation:
We can use the pathagorian theorum: A²+B²=C² now in this case it would be X²+Y²=2² we also know that X and Y are the same number in this problem because they have the same corresponding angle (triangle angles always add to 180 and since we know 2 of the angles are 45 and 90 the remaining angle will also be 45) Because of this we can change our equation to Z²+Z²=2² (I'm using Z so that we do not confuse it with another letter we've already used) from there we can go to Z∧4=2² and then we will solve the equation. Z=√2 Z also equals X and Y therefore Y=√2
I hope this helps and please let me know if there is anything you don't understand I would be happy to clarify!
Answer:
2
Step-by-step explanation:
Given the question :
Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?
Number of granolas = 6
Number of dried fruits = 10
Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)
____6____10
2___3____5
Here, the highest common factor of 6 and 10 is 2
Hence, the greatest number of snack bags she can make is 2.
Answer:

or in decimal form

Step-by-step explanation:
The midpoint of the line with endpoints
and
is
. just take the average between the points
so given the points (1,0) and (2,-10)




the midpoint is found as follows:




or in decimal form

The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer: