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svetoff [14.1K]
3 years ago
9

1) Which one of these four numbers has the greatest absolute value? (SELECT ONE answer)70-11-7

Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

70

Step-by-step explanation:

70 has the greatest absolute value because absolute value is the amount between that number and 0. If 70 is the biggest number the with the biggest absolute value is 70.

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Andrews [41]

Answer: $467.21

Step-by-step explanation:

8% of 600 = 48

600 - 48 = 552

8% of 552 = 44.16

552 - 44.16 = 507.84

8% of 507.84 = 40.6272

8% of 507.84 ≈ 40.63

507.84 - 40.63 = 467.21

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Jake wants to know if his basketball team has gotten better. Last season, Jake's team won 10 out of 20 games. This season, his t
kifflom [539]

Answer:

This season

Step-by-step explanation:

Lowest Common Multiple (LCM) of 20 and 25 = 100

10/20 * 5/5 = 50/100 = 5/10

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2 years ago
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Alex73 [517]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
DanielleElmas [232]

Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

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2 years ago
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Alexeev081 [22]
The answer is 0.91 because it is
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