Answer:
15.3 m/s
Step-by-step explanation:1) Find the gravitational potential energy using the equation :
![PE_g=mgh](https://tex.z-dn.net/?f=PE_g%3Dmgh)
![PE_g=2.5(12)(9.8)\\PE_g=294](https://tex.z-dn.net/?f=PE_g%3D2.5%2812%29%289.8%29%5C%5CPE_g%3D294)
2) Then use the equation for kinetic energy to solve for the velocity:
![KE=\frac{1}{2} mv^{2}](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D)
![294=\frac{1}{2}(2.5)(v^2)\\235.2=v^2\\\sqrt{235.2} =v\\15.3 m/s=v](https://tex.z-dn.net/?f=294%3D%5Cfrac%7B1%7D%7B2%7D%282.5%29%28v%5E2%29%5C%5C235.2%3Dv%5E2%5C%5C%5Csqrt%7B235.2%7D%20%3Dv%5C%5C15.3%20m%2Fs%3Dv)
Pi Day is celebrated on March 14th (3/14) around the world. Pi (Greek letter “π”) is the symbol used in mathematics to represent a constant.
Answer:
63° (same as Z)
Step-by-step explanation:
The question indicates that ΔXYZ is similar to ΔEDF.
By definition, when we indicate that triangle XYZ is similar to the triangle EDF, the order of the letters is important and match the congruent angles.
So, ∠X = ∠E, ∠Y = ∠D and ∠Z = ∠F
It's hard to see because the angles are quite similar in opening (56°, 63° and 61°), and the drawing doesn't seems to be to scale.
But according to the naming convention: ∠Z = ∠F
Since ∠Z = 63°, ∠F = 63°
With fractions its very easy to get 1 as a whole numer (Which is what were trying to find. ONE miles o we know how much is per hour (one hour)). All you need to do is multiply the 2/3 hour by 3/2. The numers switched. You do this with both variables, the 3/5 miles and the 2/3 hour. After this the hour variable should have turned into a 1 if done correctly. Then we multilly the miles variable by 3/2. when done correctly we get the answer of 6 9/10 miles.
After you've done this, you then know your answer. every 1 hour Izzy runs 6 9/10 miles.
Another way of saying this is Izzy runs 6.9 miles an hour or 6.9mph.
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>.</u></em><em><u> </u></em><em><u>please</u></em><em><u> </u></em><em><u>consider</u></em><em><u> </u></em><em><u>making</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>Im</u></em><em><u> </u></em><em><u>trying</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>hardest</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>provide</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>answer</u></em><em><u>!</u></em><em><u> </u></em><em><u>Happy</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>
perimeter: 16![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
multiply it by 4 (since it's a square)
area: 80
it's a square so all you need to do is multiply it by itself
4 x ![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
16 x 5 (squared them)
80