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3 years ago

6

Which linear equality will not have a shared solution set with the graphed linear inequality? y >2/5 x + 2 y <-5/2 x – 7 y

>-2/5 x – 5 y < 5/2x + 2

2 answers:

Angelina_Jolie [31]3 years ago

8 0

Answer:y < -5/2x -7

Step-by-step explanation:

just answered correctly on edge

jonny [76]3 years ago

6 0

Answer: B

Step-by-step explanation:

just took the test.

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What is the product? (3x-6) (2x^2 -7x+1)

STALIN [3.7K]

<u>Answer-</u>

$\left(3x-6\right)\left(2x^2-7x+1\right)=6x^3-33x^2+45x-6$

<u>Solution-</u>

Given the two polynomials are $3x-6, 2x^2 -7x+1$

So their product will be,

$=\left(3x-6\right)\left(2x^2-7x+1\right)$

Distributing the Parentheses,

$=3x\cdot \:2x^2+3x\left(-7x\right)+3x\cdot \:1+\left(-6\right)\cdot \:2x^2+\left(-6\right)\left(-7x\right)+\left(-6\right)\cdot \:1$

Applying minus-plus rules,

$=3\cdot \:2x^2x-3\cdot \:7xx+3\cdot \:1\cdot \:x-6\cdot \:2x^2+6\cdot \:7x-6\cdot \:1$

Simplifying further,

$=6x^3-33x^2+45x-6$

4 0

3 years ago

Read 2 more answers

A’B’C’ is a dilation image if ABC which is the correct description of the dilation

Sav [38]

Answer:

The dilation is an enlargement

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal and this ratio is called the scale factor

In this problem Triangles A'B'C' and ABC are similar by AA Similarity Postulate

Let

z------> the scale factor

so

$z=\frac{A'C'}{AC}$

substitute the values

$z=\frac{2+8}{2}$

$z=\frac{10}{2}=5$

The scale factor is greater than 1

therefore

The dilation is an enlargement

3 0

3 years ago

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12 is 30% of what?

alexgriva [62]

12 = 30% of what
12 = 0.30x
12 / 0.30 = x
40 = x.......so 12 is 30% of 40

5 0

3 years ago

A side of the triangle below has been extended to form an exterior angle of 164". Find

Arada [10]

Given:

Measure of exterior angle = 164°

The measure of opposite interior angles are x° and 53°.

To find:

The value of x.

Solution:

According to the Exterior Angle Theorem, in a triangle the measure of an exterior angles is always equal to the sum of measures of two opposite interior angles.

Using Exterior Angle Theorem, we get

$x^\circ+53^\circ=164^\circ$

$x^\circ=164^\circ-53^\circ$

$x^\circ=111^\circ$

$x=111$

Therefore, the value of x is 111.

3 0

3 years ago

timofeeve [1]

Answer:

4.

Step-by-step explanation:

(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α

But sec^2 α = 1 + tan^2 α so

sec^2 α - tan^2α = 1 + tan^2 α - tan^2α

= 1

so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α

1/4 * x = 1

x = 4.

6 0

3 years ago