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PtichkaEL [24]
3 years ago
8

Find the equation of a line that contains the points (5.-7) and (-5,5). Write the equation in slope-intercept form, using

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Answer:

       

.

Step-by-step explanation:

You might be interested in
Andre tried to solve the equation 1/4(x + 12) = 2. What was his mistake? *
Umnica [9.8K]

Answer:

x=-4

Step-by-step explanation:

x+12=8    

x=8-12

Andre did not multiple both by four to get the exact whole number. He also, didnt subtract 12 which is not possible due to it being multiplied by 1/4.

5 0
3 years ago
How many solutions does x²+3x=3 have?
aev [14]

Answer:

2 (real) solutions.

Step-by-step explanation:

A quadratic always has two solutions, whether they are real or complex.

Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).

In the case of

x^2+3x = 3, or

x² + 3x -3 = 0

we apply the quadratic formula to get

x =  (-3 +/- sqrt(3^2+4(1)(3))/2

to give the two solutions

{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}

both of which are real.

4 0
3 years ago
Find the volume of a rectangular prism with dimensions 21 in. by 20 in. by 19 in., to the nearest hundredth cubic foot
Maurinko [17]

Answer:

The dimensions of a rectangular prism are 21 in. by 20 in. by 19 in.

To find:

The volume of the rectangular prism.

Solution:

Let the length, breadth and height are 21 in, 20 in and 19 in respectively.

Volume of the rectangular prism is

V=Length\times Breadth\times Height

V=21\times 20\times 19

V=7980

Therefore, the volume of the rectangular prism is 7980 cubic inches.

6 0
3 years ago
A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude
DaniilM [7]

Answer:

The answer is "\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\"

Step-by-step explanation:

Given values:

\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39

Using formula:

\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\

Put the values in the above formula:

\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\

4 0
3 years ago
In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s
Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 38.6

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 210}{38.6}

X - 210 = -1.28*38.6

X = 160.59

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0
3 years ago
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