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alina1380 [7]
4 years ago
14

Solve using the Quadratic Formula. Please show your work. 4x^2+13x=12

Mathematics
1 answer:
Len [333]4 years ago
5 0

Answer:

x=3/4 or x= -4

Step-by-step explanation:


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Last year, 140 people in a community had cell phones. This year, the number of people in the community with cell phones has incr
Murljashka [212]

the number has been increased by 79

6 0
3 years ago
What two numbers multiply to -42 but also add up to -11
spayn [35]

Answer:

-14 *3 and -14 + 3

Step-by-step explanation:

8 0
4 years ago
What is the slope of the line that contains the points (-2,2) and (3,4)
malfutka [58]

<u><em>Answer: B. 2/5 *The answer must have a fraction.</em></u>

Explanation:

Slope-intercept form: → y=mx+b

m: represents the slope and is constant.

b: represents the y-intercept.

Used rise/run.

\frac{rise}{run}

x^1,y^1=(-2,2)

x^2,y^2=(3,4)

You had to find the slope by using formula.

Slope=\frac{y^2-y^1}{x^2-x^1}

\frac{4-2}{3-(-2)}

subtract by the numbers and add the numbers too.

\frac{4-2=2}{3-(-2)=3+2=5}

=\frac{2}{5}

Hope this helps!


4 0
3 years ago
Find the missing side. Round your answer to the nearest tenths.<br><br> X=
Lapatulllka [165]

Answer:

   16.5 ≈ x

Step-by-step explanation:

We have a right triangle where we know 1 side, 1 angle and we need to find another side. We can use trigonometric functions to find the missing side.

The tangent function definition is

tan α = opposite side/ adjacent side

In our problem

   tan 70° = x/ 6, multiply both sides by 6 to isolate x

6 · tan 70° = x, use the calculator (make sure is set in degrees)

    16.4848 ≈ x , round to the nearest tenths

         16.5 ≈ x


3 0
2 years ago
​34% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mo
tamaranim1 [39]

Answer:

solution below

Step-by-step explanation:

The question says 6 working mother's were selected so <u>n = 6</u><u> </u><u>not</u><u> </u><u>0</u><u>.</u><u>6</u>

We are expected to find

P(X = 0,1,2,3,4,4,6)

1. <u>When x = 0</u>

6C0*(0.34)⁰*(0.66)⁶

= 1 *1* 0.827

= 0.0827

<u>2. When X = 1</u>

6C1*(0.34)¹*(0.66)⁵

= 6 x 0.34 x 0.252

= 0.2555

<u>3. When X = 2</u>

6C2*(0.34)²*(0.66)⁴

= 15 x 0.1156 x 0.1897

= 0.3289

<u>4. When x = 3</u>

6C3*(0.34)³*(0.66)³

20 x 0.039304 x 0.2875

= 0.2599

<u>5. When X = 4</u>

6C4*(0.34)⁴*(0.66)²

= 15 x 0.01336 x 0.4356

= 0.8729

<u>6. When x = 5</u>

6C5*(0.34)⁵*(0.66)¹

= 6 x 0.0045 x 0.66

= 0.01782

<u>7. When x = 6</u>

6C6*(0.34)⁶*(0.66)⁰

1 x 0.0015 x 1

= 0.0015

5 0
3 years ago
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