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3 years ago

PLS CHECK IF MY ANSWER IS CORRECT! 40 POINTS!

Advanced Placement (AP)

1 answer:

Nookie1986 [14]3 years ago

8 0

As someone who is taking an electrical theory course in college, your total resistances and total currents are definitely correct. Furthermore, your final statement is correct (given that your lightbulb currents are correct).

I'm not completely sure if your current in the lightbulbs are correct because I'm pretty "Brain-ed" out from the semester and electrical theory isn't my best subject. I'd double check with some friends on those two statements.

I think the trouble is that I'm having a hard time following your logic. Overall, it appears you do have logical reasoning. Hope I helped a bit!

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lara [203]

Answer:

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Explanation:

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3 years ago

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3 years ago

A 1.0 kg lump of clay is sliding to the right on a frictionless surface with speed 2 m/s . It collides head-on and sticks to a 0

Aleks [24]

Answer:

Explanation:

Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,

mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = -4m/s to the left. using conservation law of momentum;

M1U1 + M2U2 = V (M1 + M2)

(1.0 × 2) + (0.5 × -4) = V (1 + 0.5)

2 -2 = V (1.5)

0 = V (1.5)

divide both side by 1.5

0/1.5 = V 1.5/1.5

V = 0

since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero

1/2 V(M1 +M2)

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3 0

3 years ago

If the wait time is less than 30 minutes for 75% of all patients in the emergency room, what is the probability that the

Greeley [361]

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less is 0.0020

<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

The sample size (n) = 55 patients
Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion $\mathbf{\hat p}$ can be computed by using the expression:

$\mathbf{\hat p = \dfrac{x}{n}}$

$\mathbf{\hat p = \dfrac{32}{55}}$

$\mathbf{\hat p =0.582}$

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

$\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}$