Answer:
The GCF for the variable part is ab².
GCF<em>Variable</em>=ab²
Multiply the GCF of the numerical part 5 and the GCF of the variable part ab².
5ab²
Step-by-step explanation:
Answer:
AFE = 99°
Step-by-step explanation:
Correct on E2020
Gauss's approach is to add the same sequence in reverse order, namely
S=1+3+5+7+......+95+97+99
S=99+97+95+......+7+5+3+1
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2S=(1+99)+(3+97)+(5+95)+......(95+5)+(97+3)+(99+1)=50*100=5000
=> sum = (2S)/2 = 5000/2=2500.
The general equation for a straight line is
, where m is the slope, and b is the y-intercept. Plugging in numbers, your equation will be
.
Use the equation
t = -b / (2a)
where:
a = -16
b = 30.4
Plug these values into the equation.
b)
Evaluate h(t) at the time of maximum height. The time of maximum height is the value found in previous part.
c)
Set h(t) equal to 3 and solve for t.
3 = -16t2 + 30.4t + 5
0 = -16t2 + 30.4t + 2
Solve this quadratic equation for t. I suggest you use the quadratic formula to solve for.
