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3 years ago

A car uses !5 gallons of gas to go 330 miles. How much will the car need to go 450 miles?

1 answer:

3 0

This is how I do it. 330÷5=66. Now for every gallon we have 66 miles. Now divide 450 by 66 to see how many gallons we need. 450÷66=6.81818181818 which rounds to 6.8. The car will need 6.8 gallons of gas to go 450 miles

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Reduce To Simplest Form.<br><br>2/2 + 1.75 - 44/25 =

Soloha48 [4]

Answer/Step-by-step explanation:

First, we should make each fraction, decimal, whole number into fraction and number form.

So, 2/2 = 1.

1.75 is 1 3/4.

44/25 is 1 19/25.

Now we have our equation, now we can do this equation easier.

1 + 1 3/4 - 1 19/25.

1 + 1 3/4 = 2 3/4.

Then, we turn both numbers to Decimal Form.

2 3/4 = 2.75

1 19/25 = 1.76.

When we divide 19 by 25, we get 0.76.

Then we subtract the decimals.

We should start right and end left.

5 - 6 = -1, we need to borrow one from the closest digit to the left, which is 7. Now we have 15 - 6 = 9.

Next, we have 6 - 7 = -1, we need to borrow one from the closest digit to the left, which is 2. Now we have 16 - 7 = 9.

Our answer right now is 0.99.

Lastly, 1 - 1 = 0.

Which leaves us with the answer: 0.99 (Zero and Ninety Nine Hundredths.)

Best of Luck to you.

If you have any questions, feel free to comment below.

5 0

3 years ago

Which is the graph of y =(x) - 2?

Likurg_2 [28]

Answer: i dont see the graphs

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

wlad13 [49]

Answer:

$\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}$

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

$f(x)=\frac{u(x)}{v(x)}\\$ , the derivative is express as

$\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }$

from $y=lnx/x^{2}$

we assign u(x)=lnx and v(x)=x^2

and the derivatives

$\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\$ .

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e $y=lnx\\\frac{dy}{dx}=\frac{1}{x}$