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3 years ago

15

limo service charges a base rate of $30 and then No $25 per mile. write an equation that would show the total cost of a limo rid

e. Then, find the cost if you needed the limo for a 20 mile trip? How about a 60 mile trip?

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

30 + 25x = ???

x=20

25× 20 +30 = ???

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the actual length of wall c is 4 m . to represent wall c noah draw a segment 16cm long what scale is he using explain your reaso

Gnoma [55]

Answer:

1/25

Step-by-step explanation:

1 m = 100 cm

4m x 100 = 400 cm

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3 years ago

Geometry picture added

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This is because y and 108° are vertex angles meaning they are both equal to each other. X is 72 because it’s form a supplementary angle with 108°. So what I did to find x is I subtracted 108 from 180 to get 72°. Then I know x and z are vertex angles meaning that z is also equal to 72°

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the longer diagonal is 4 more than the shorter diagonal of a kite. The area is 5 times the shorter diagonal. If the shorter side

Valentin [98]

Correct answer:
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Since this question provides the area of the kite and length of one diagonal, plug that information into the equation to solve for the missing diagonal.

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3 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The

Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that $n = 387, \pi = \frac{298}{387} = 0.77$

84% confidence level

So $\alpha = 0.16$ , z is the value of Z that has a p-value of $1 - \frac{0.16}{2} = 0.92$ , so $Z = 1.405$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8$

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

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3 years ago