Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that 
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 
So we have to solve the following system:






There were 7 small boxes and 14 large boxes shipped.
Answer:
23 years
Step-by-step explanation:
Step 1: Calculate the rate constant (k) for the radioactive decay
A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.
ln [A]/[A]₀ = - k.t
k = ln [A]/[A]₀ / -t
k = ln 0.97 [A]₀/[A]₀ / -1 year
k = 0.03 year⁻¹
Step 2: Calculate the half-life of the substance
We will use the following expression.
= ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years
Xjsksnsosnsosnsosnd. Didnrjebs didneisneiw sjs did god Factor. x^2−10x−11
(x+11)(x−1)
(x+11)(x+1)
(x−11)(x+1)
(x−11)(x−1)
Answer:
9n+18(2n-6)+13
Step-by-step explanation:
First, use distributive property to eliminate the parenthesis:
9n + 18(2n -6) + 13
9n + 36n - 108 + 13
Next, combine like terms:
9n + 36n - 108 + 13
45n - 108 + 13
45n + 121
Hope this helps!!
Alan~