9514 1404 393
Answer:
13.8654599313 and -0.8654599313
Step-by-step explanation:
If one of the numbers is x, then the other is 13-x, and their product is ...
x(13 -x) = -12
x^2 -13x = 12 . . . . multiply by -1 and simplify
x^2 -13x +6.5^2 = 12 +6.5^2 . . . . complete the square
(x -6.5)^2 = 54.25
x -6.5 = √54.25
x = 6.5 +√54.25 ≈ 13.8654599313
and the other number is ...
13 -x = 13 -13.8654599313 = -0.8654599313
The two numbers are 13.8654599313 and -0.8654599313.
Answer:
I would start at ( -2, -0) and make a line
Step-by-step explanation:
Answer:
width = 12 ft
Step-by-step explanation:
Given the figure of the pond and the fact that the corners form a right triangle that is across from the string of flags, you can use the Pythagorean Theorem to solve for the width of the triangle that is formed by the flags:
a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the diagonal or hypotenuse. Using 16 for 'a' and 20 for 'c':
16² + b² = 20²
256 + b² = 400
Subtract 256 from both sides: 256 - 256 + b² = 400 - 256 or b² = 144
Take the square root of both sides: √b² = √144 or b = 12 ft
Ummm...... i would say B, i hope that helped! if not, forgive me :)
The easiest method to solve problems like this is to graph the inequalities given and shade the regions that make them true. When you have properly shaded all of the regions, you will find that you have a region which is bounded on all four sides by one of the inequalities, and then you can find the x and y values which correspond to the vertices of the shaded region.
You didn't provide a function that you are trying to maximize in this example, but the idea is that you take all of the (x,y) points which correspond to the vertices and plug them into your objective function. The one which produces the largest value maximizes it (it is a similar process for minimizing it, but you'd be looking for the smallest value). Let me know if you need more help than that, or would like me to work out the example you have provided (I will need an objective function for it though).
