What is the value of x and y?

Length 21cm area 315cm2 find the breath

Ronch [10]

Answer:

Breadth = 15 cm

Step-by-step explanation:

Area = length x breadth

315 = 21 x breadth

$\frac{315}{21} = \frac{21}{21} \times breadth$ [ dividing both sides by 21 ]

$15 = 1 \times breadth\\\\breadth = 15 \ cm$

4 0

2 years ago

Read 2 more answers

Suppose five days ago is Friday. What day of the week will be the day after tomorrow be?

MA_775_DIABLO [31]

Given Situation : If 5 days ago is Friday, then what day of the week will be the day after tomorrow.
Answer:
If 5 days ago is Friday.
DAY1 is
- Saturday
DAY 2 is
- Sunday
DAY 3 is
-Monday
DAY 4 is
- Tuesday
DAY 5 is today
- And today is Wednesday
DAY 6
- Tomorrow is Thurdays
DAY 7
- Which is the day after tomorrow is Friday

Thus, the day that we are looking is Also Friday.

8 0

2 years ago

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write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

What is the AREA of this figure?

elena-14-01-66 [18.8K]

Answer:

532m squared is the answer

Step-by-step explanation:

Split the shape into two shapes

one will be a square and the other one a triangle

1) since the length and the width of the square is 18m just Multiply

18x18=324m squared

2) look carefully the width of the square you split is equal to the base of the triangle, so you connect the 18 and the 8 together.

18+8=26m squared

3) Now solve the triangle since you know the height which is 16m squared.

A=lw/2

26x16=416

416 divided by 2 is 208

4) finally just Add

208+324=532m squared

Hopes this helps!

7 0

3 years ago

A=9 inches, b=12 inches, c=, is the hypotenuse known or unknown?

s2008m [1.1K]

Unknown. C is the hypotenuse, but this problem is solvable.

5 0

3 years ago