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Kazeer [188]
3 years ago
10

I need help please...

Mathematics
1 answer:
telo118 [61]3 years ago
7 0
The answer is b
Area=[pi]r2
= [pi](12 in)2
=452.16 in2
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Somebody please help me!
GREYUIT [131]

Answer:

second option, IQR = 13-6 = 7 and Range = 17-6 = 11

Step-by-step explanation:

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3 years ago
Eric has an estimated income of $2,270 per month. After budgeting his expenses he has found that he has about $836 remaining. If
vladimir1956 [14]

1,434÷2,270=0.63×100=63%





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4 years ago
The diameter of a regulation soccer ball is about 5 inches. This number was graphed on a number line. 8 DO + S-651 1 et Which po
gizmo_the_mogwai [7]

Answer:

D.

Step-by-step explanation:

d is the answer

8 0
3 years ago
13m/1m = ?/100cm I need to have this answer quick, please respond as fast as you can, thank you so much​
Arte-miy333 [17]

Answer:

The answer is 13 m/1 m = <u>1300 cm</u>/100 cm.

Step-by-step explanation:

Given:

13m/1m = ?/100cm.

Now, to find the answer in the place of <u>? </u> .

13m/1m = ?/100cm.

As, <em><u>1(m) metre =  100(cm) centimetre.</u></em>

So, by multiplying 13 m with 100 we get:

13 m\times 100 = 1300 cm.

Thus, 13 m/1 m = 1300 cm/100 cm.

Therefore, the answer is 13 m/1 m = 1300 cm/100 cm.

3 0
4 years ago
How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
3 years ago
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