Answer:
Well, in reality, all circles are similar to each other. They will all have the same angles, and they don't really have side lengths. So, they are similar.
But to PROVE they are similar, we will transform Circle C to match circle E.
Circle C has a center at (-3, 1), and Circle E has a center of (4, 9). For Circle C to have the same center as Circle E, we will translate Circle C 7 units to the right, and 8 units up.
Since Circle C has a radius of 4, and Circle E has a radius of 3, dilate Circle C by a factor of 3/4. That way, the radius is 3 units as well.
And there you go! The two circles will map perfectly on top of each other.
Hope this helps!
Question 4
The magnitude;
Using Pythagoras theorem,
(-200)² + (-530)² = 320900
Length = √320900
= 566.5 mi
To get the angle
Tan θ = opposite/adjacent
= 200/530
= 0.3774
θ = tan^-1 (0.3774)
= 20.67
≈ 21°
The direction from the Cartesian plane is south of west.
Therefore, the magnitude and the direction will be;
About 566.5 mi, 21° south of west
Question 5.
To get the resultant of two vectors we just add the two vectors given.
This involves adding the corresponding values.
Thus, for <-6,5> and <6,-5>
Resultant vector = <(-6+6),(5+-5>
= <0,0>
To find the average of the data
First, we must solve for the radius of the sphere:
V=
r=(3
)
r=(3*
)
r≈5.99
Second, we must solve for surface area:
A=4
A=4*
*
A≈450.88
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
