A(n) = –3 • 2⁽ⁿ⁻¹⁾
for n = 1 , A₁ = -3.(2)⁰ = -3
for n = 2 , A₂ = -3.(2)¹ = -6
for n = 3 , A₃ = -3.(2)² = -12
for n = 4 , A₄ = -3.(2)³ = -24
...........................................
for n = 8 , A₈ = -3.(2)⁷ = -384
Answer:
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#1.
[4x = -12y + 16 and x + 3y = 4]
One answer
#2.
Here, y = 4x + 3
y - 4x = 3
Multiply by 2,
2y - 8x = 6
Compare with second equation,
6 ≠ 3
In short, System of Equation does not have any solution. [ Option D ]
#3.
2y=6
3x-6y=18
Divide first equation by 2: y=3
Substitute y=3 into second equation: 3x-6(3)=18
Solve for x: 3x=36 x=12
Therefore there is only one solution: x=12 y=3
#4.
y - 7x = -14
7y - 49x = -2
Rewrite the first equation as "y =" so that it can be substituted into the second equation and solve for x.
y = 7x - 14
7(7x - 14) - 49x = -2
49x - 98 - 49x = -2
-98 = -2
Since the variables cancel and the equation is not true there is no solution.
The lines are parallel and will not intersect.
Answer:
52
Step-by-step explanation:
If JK bisects the angle, the two angles are equal
6x+2 = 8x-6
Subtract 6x from each side
6x-6x+2 = 8x-6x-6
2 = 2x-6
Add 6 to each side
2+6 =2x-6+6
8 =2x
Divide by 2
8/2 =2x/2
4 =x
Now find angle LJM, which is the sum of the two angles
6x+2 + 8x-6
14x -4
14*4-4
56-4
52
Answer:10
Step-by-step explanation:
