3 years ago

( 3 + 2i ) + ( 6 - 8i )

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

9-6i is the answer, combine like terms

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Is (2, 7) a solution to this system of equations?<br> x + y = 9<br> 3x + 13y - 9

alukav5142 [94]

Answer:

Step-by-step explanation:

Assuming that you put the wrong sign for the second equation if you plug (2,7) into the two equations it only works for one equation.

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Alina spent no more than $45 on gas for a road trip. The first gas station she used charged $3.50 per gallon and the second gas

xenn [34]

The answer is C.Your welcome

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Evaluate the expression for the given value of the variable. |b| + b^3 ; b = -2, please show work!

Katen [24]

So b=-2 so you plug b in

l(-2)l + (-2)^3.

The absolute value of -2 is just 2 so now it is

2 + (-2)^3.

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2 years ago

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trapecia [35]

Answer:

Step-by-step explanation:

sorry im not sure

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3 years ago

The equation of the hyperbola that has a center at ( 6 , 9 ) , a focus at ( 11 , 9 ) , and a vertex at ( 9 , 9 ) (x−C)^2/A^2−(y−

MrMuchimi

Answer:

$A=-3$

$C=6$

$B=4$

$D=9$

Step-by-step explanation:

From the question we are told that:

Center of hyperbola at ( 6 , 9 )

Focus of hyperbola at ( 11 , 9 )

Vertex of hyperbola at ( 9 , 9)

Equation of hyperbola $\frac{(x-C)^2}{A^2} -\frac{(y-D)^2}{B^2}=1$

Generally the C and D of the hyperbola equation is mathematically given by

$Centers (6,9)$

$C=6$

$D=9$

Generally the A and B a of the hyperbola equation is mathematically given by

$A=x_c-x_v$

$A=6-9$

$A=-3$

$C'=x_c-x_f$

$C'=6-11$

$C'=-5$

Therefore with Center,Focus ,Vertex on the same line

$B^2=C'^2-A^2$

$B^2=(-5^2)-(-3^2)^2$

$B^2=(25)-(9)$

$B^2=16$

$B=4$

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2 years ago