Question:
In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller is 6.00 m, and, while being driven into rotation around a fixed axis, its angular position is expressed as θ = 2.70t² − 0.900t3³
where θ is in radians and t is in seconds.
(a) Find the maximum angular speed of the roller.
(b) What is the maximum tangential speed of a point on the rim of the roller?
(c) At what time t should the driving force be removed from the roller so that the roller does not reverse its direction of rotation?
(d) Through how many rotations has the roller turned between t = 0 and the time found in part (c)?
Answer:
a. 2.7rad/s
b. 8.1 m/s
c. 2 s
d. 3.6 rad
Explanation:
Answer:
Explanation:
Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :
F = m × a
F is the applied force
m is the mass of the object
a is the acceleration due to gravity
We need to find the dimensions of force. The dimension of force m and a are as follows :
So, the dimension of force F is, . Hence, this is the required solution.
Answer:
The combinations are
1. C ,
2. C ,
Explanation:
The force between two charges q and Q is given by Coulomb's law.
The coulomb force is given by
Where, r be the distance between two charges
According to the question,
r = 15 cm, Q = C, q = C , F = 12 N
Force remains same, distance remains same
so the product of Q and q be same
The product of Q and q is
So other combination of charges are
1. C ,
2. C ,
Answer:
52 m/s
Explanation:
Wavelength is the distance between two successive crests. Two crests make one circle hence 16 cycles are equal to 16 wavelengths. Each wavelength is equal to 208/16=13 m long
Speed of wave is given as the product of wavelength and frequency, expressed as
S=fw
Where f is the frequency and w is the wavelength
Substituting 13 m for w and 4 Hz for f then
S=4*13=52 m/s
Therefore, the speed is equivalent to 52 m/s
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