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erastova [34]
3 years ago
6

If a circle was flattened by pushing down on it, it would most likely form into the shape of an(1) ___ which has(2)___focal poin

ts.
1.
a) oblonga
b) polygonan
c) ellipse

2.

a) one
b) two
c) three
Physics
2 answers:
worty [1.4K]3 years ago
5 0
C. Eclispe

B. 2
plz rate comment and thank :3
Bess [88]3 years ago
5 0

Answer: If a circle was flattened by pushing down on it, it would most likely form into the shape of an <u><em>ellipse </em></u>which has <u><em>two </em></u>focal points.

Explanation:

An ellipse is defined as the enclosed curve with two focal points.Sum of the Distance of any point on the curve from the two focal point remains constant.For example: An orbit of the earth is elliptical shape.

So, when we flattened circle we will obtain an ellipse with 2 focal points.

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a 2kg object is moving horizontally with a speed of 4 m/s.how much net force is required to keep the object moving at this speed
Elza [17]
If the object is moving in a straight line with constant speed,
that's a description of " acceleration = zero ".

Zero acceleration means zero net force on the object.

NO net force is 'required' to keep an object moving in a straight line
at constant speed.  In fact, if there IS any net force on the object,
then either its speed or its direction MUST change ... there's no way
to avoid it.

None of this depends on the object's mass, or on the speed or direction
of its motion.
8 0
3 years ago
A bullet is fired horizontally from a handgun at a target 100.0 m away. If the initial speed of the bullet as it leaves the gun
Lera25 [3.4K]

Answer:

The distance is 0.53 m.

Explanation:

Given that,

Target distance = 100.0 m

Speed of bullet = 300 m/s

We need to calculate the total time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{100.0}{300}

t=0.33\ sec

Now, consider vertical motion of bullet.

Initial velocity of bullet in vertical direction = 0 m/s

We need to calculate the vertically distance

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

s=0+\dfrac{1}{2}\times9.8\times(0.33)^2

s=0.53\ m

Hence, The distance is 0.53 m.

5 0
3 years ago
For states with larger values of n that admit a d subshell, the d subshell is at even higher energy than the p subshell. In fact
frosja888 [35]

Answer:

Explanation:

Correct order of energy of energy states within an atom is as follows

1s , 2 s, 2 p 3 s ,3 p, 4s , 3d,  4p, 4p,5s etc.

There is discrepancies in this order due to overlapping of outer orbitals with inner orbitals so sometimes outer orbitals have lower energy.

4 0
3 years ago
A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volum
Alecsey [184]
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
4 0
3 years ago
Read 2 more answers
Consider the hydrogen atom as described by the Bohr model. The nucleus of the hydrogen atom is a single proton. The electron rot
riadik2000 [5.3K]

To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

a_c = \omega^2 r

Here,

\omega =Angular velocity

r = Radius

Our values are given as,

\omega = 4.12*10^{16}rad/s

r = 5.29*10^{-11}

Replacing,

a_c = (4.12*10^{16})^2( 5.29*10^{-11})

a_c = 8.979*10^{22}m/s^2

Therefore the electron's centripetal acceleration is 8.979*10^{22}m/s^2

7 0
3 years ago
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