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erastova [34]
3 years ago
6

If a circle was flattened by pushing down on it, it would most likely form into the shape of an(1) ___ which has(2)___focal poin

ts.
1.
a) oblonga
b) polygonan
c) ellipse

2.

a) one
b) two
c) three
Physics
2 answers:
worty [1.4K]3 years ago
5 0
C. Eclispe

B. 2
plz rate comment and thank :3
Bess [88]3 years ago
5 0

Answer: If a circle was flattened by pushing down on it, it would most likely form into the shape of an <u><em>ellipse </em></u>which has <u><em>two </em></u>focal points.

Explanation:

An ellipse is defined as the enclosed curve with two focal points.Sum of the Distance of any point on the curve from the two focal point remains constant.For example: An orbit of the earth is elliptical shape.

So, when we flattened circle we will obtain an ellipse with 2 focal points.

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Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

1.5 = 0.5 × V₂

Divide both side by 0.5

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A 1.50 µF capacitor and a 3.50 µF capacitor are connected in series across a 2.50 V battery. How much charge (in µC) is stored o
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Explanation:

The given data is as follows.

      C_{1} = 1.50 \times 10^{-6} F

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Hence, calculate the equivalence capacitor as follows.

    \frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}

    \frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}

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Now, we will calculate the charge across each capacitance as follows.

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Thus, we can conclude that 2.65 \mu C is the charge stored on each given capacitor.

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