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3 years ago

Determine the vertical asymptote for the rational function f(x) = x-4 over 3x +2

Mathematics

1 answer:

Ghella [55]3 years ago

8 0

Answer: (b) x = -2/3

<u>Step-by-step explanation:</u>

The vertical asymptote is the restriction on x.

The denominator cannot be equal to zero so that it the restriction.

Set the denominator equal to zero and solve for x to find the asymptote.

3x + 2 = 0

3x = -2

x = -2/3

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Pls help do you know 500000x4000000000➗4

Snowcat [4.5K]

Answer:

500000000000000

Step-by-step explanation:

multiply 500000 by 4000000000 (2000000000000000), then divide by 4 (500000000000000)

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3 years ago

Which equation has the same solution as w / 3.9 = 3? A. w+0.6=1.9 B. w-0.6 = 11.1 C. w+1.03=2.93 D. w-1.03=8.24

cestrela7 [59]

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

<em>Check all that applies</em>

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Learn more about equation:

brainly.com/question/2972832

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3 years ago

Jill works 2.5 hours and earns $37.5. How many hours does she have to work to receive $240?

SIZIF [17.4K]

16 Hours because we can calculate the compensation per hour by doing 37,5/2,5=15 and then doing 240/15=16 to find how many hours does it take to get 240$

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3 years ago

Sketch the following to help answer the question. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals

Troyanec [42]

Answer:

B. 8m

Step-by-step explanation:

Given:

The figure is a kite having points QRST.

It has short diagonal QS.

Long diagonal RT

Diagonal Intersect at point P.

side QR = 10m

Diagonal QS = 12m

We need to find the length of segment RP.

According Diagonal Property of kite.

It states that Diagonals of Kite perpendicularly bisects each other.

QP = PS

RP = PT

But QS = QP + PS

QS = QP + QP

QS = 2 QP

QP = $\frac{1}{2}$ QS = $\frac{1}{2}\times 12 = 6 m$

Now In Δ QPR

m∠ P = 90° (Diagonals of a kite is perpendicular to each other)

Now by Pythagoras theorem;

$QR^2 = QP^2+RP^2\\RP^2 = QR^2 - QP^2\\RP^2 = (10)^2- (6)^2\\RP^2 = 100 -36\\RP^2=64\\RP = \sqrt{64} =8\ m$

Hence the Length of segment RP is 8m.

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3 years ago

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Salsk061 [2.6K]

Triangular
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3 years ago