All categories

3 years ago

Determine the vertical asymptote for the rational function f(x) = x-4 over 3x +2

Mathematics

1 answer:

Ghella [55]3 years ago

8 0

Answer: (b) x = -2/3

<u>Step-by-step explanation:</u>

The vertical asymptote is the restriction on x.

The denominator cannot be equal to zero so that it the restriction.

Set the denominator equal to zero and solve for x to find the asymptote.

3x + 2 = 0

3x = -2

x = -2/3

You might be interested in

Given the functions, fx) = x - 8 and g(x) = x2 + x - 1, perform the indicated operation. When applicable, state the domain

adell [148]

Answer:

Step-by-step explanation:

(fg)(x) = f(x) × g(x)

= (x - 8)(x² + x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis

= x³ + x² - x - 8x² - 8x + 8 ← collect like terms

= x³ - 7x² - 9x + 8 → A

There are no restrictions on the domain.

4 0

4 years ago

Question 3

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

Big Brain

7 0

3 years ago

CAN SOMEONE BE NICE AND HELP ME K THANKS;)

EleoNora [17]

$volume = base \times length \times height$

4 0

3 years ago

Please at least help me cause I have no idea

Blababa [14]

Answer:

Solving the given formula for v2 gives us:

$a(t_2-t_1)+v_1 = v_2$

Step-by-step explanation:

Solving an equation for a particular variable means that the variable has to be isolated on one side of the equation.

Given equation is:

$a = \frac{v_2-v_1}{t_2-t_1}$

Multiplying both sides by t2-t1

$(t_2-t_1) . a = \frac{v_2-v_1}{t_2-t_1} . (t_2-t_1)\\a(t_2-t_1) = v_2-v_1$

Adding v1 to both sides of the equation

$a(t_2-t_1)+v_1 = v_2-v_1+v_1\\a(t_2-t_1)+v_1 = v_2$

Hence,

Solving the given formula for v2 gives us:

$a(t_2-t_1)+v_1 = v_2$

8 0

3 years ago

Max runs 3 laps around the track in 8 min. How many minutes per lap is that?

ICE Princess25 [194]

Answer:

Step-by-step explanation:

8/3 = 2.6666 (repeating 6)

so rounded about 2.7 minutes per lap :)

3 0

3 years ago