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malfutka [58]
3 years ago
15

-8(3m-3)=-5m+10(-3m-5) ? :(

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

m=-74/11

Step-by-step explanation:

Distribute the 8 through the Parenthesis.

-24=24=-5m+10(3m-5)

Collect Like terms

-24+24=-35m-50

Move terms

-24m+35m=-50-24

11m=-50-24

11=-74

Divide by 11

Answer- -74/11

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Virty [35]
See attached. The trick is to use similar triangles.

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3 years ago
Rewrite the expression in the form... (PLZ HELP QUICK I'LL GIVE BRAINLIEST)
ivanzaharov [21]

Answer: 3*z^\frac{2}{9}

Step-by-step explanation:

The exponent 1/3 is the same thing as cube rooting the expression.

\sqrt[3]{27\sqrt[3]{z^2} }

3*z^{2/9}

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4 0
3 years ago
Can someone help Plz
MArishka [77]

Answer:

D = 67 inches

Step-by-step explanation:

The trend line is y = x+2  where x is the height

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4 0
3 years ago
Read 2 more answers
A circular field has a area of 14400 sq ft <br> What is the diameter of the field?
Bingel [31]

Answer:

240/sqrt(pi)

Step-by-step explanation:

We know that the area of a circle is $pi*r^2$, and we also know that the diameter of a circle is equal to $2r$.

Let's first make an equation for this problem.

pi*r^2=14400

Dividing both sides by pi, we get

r^2=14400/pi

Now, taking the square root of both sides gives us

r=120/sqrt(pi)

We are trying to find the diameter, which is twice the size of the radius.

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2r=240/sqrt(pi)

6 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
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