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3 years ago

Solve (26/57)=(849/5x)

2 answers:

7 0

Step 1 26/57 = (849/5)*x // - (849/5)*x

Step 2 26/57-849/5*x = 0 // - 26/57

step 3 x = -26/57/(-849/5)

Step 4 x = 130/48393

Gnesinka [82]3 years ago

4 0

Cross multiply 26*5x = 849 * 57 130 x = 48393 x = 48393 / 130 x = 372.25

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Please help, please show ur work

DENIUS [597]

Answer:

y=3

y=9

Step-by-step explanation:

y=3×0+3

y=3×1+3

5 0

3 years ago

Read 2 more answers

Combine the like terms to create an equivelant expression -3x-6(-1)

Elza [17]

Answer:

-3x+6

Step-by-step explanation:

-3x-6(-1)

First, multiplying two negatives equals a positive: (-)×(-)=(+). Then,

multiply the numbers -3×+6×1 = -3x+6. Then, you got the answer and the answer is -3x+6

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3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

Solve the given system of equations2y=x+93x-6y=-15

attashe74 [19]

Answer:

No solutions

Explanation:

The given system of equations is

2y = x + 9

3x - 6y = -15

To solve the system, we first need to solve the first equation for x, so

2y = x + 9

2y - 9 = x + 9 - 9

2y - 9 = x

Then, replace x = 2y - 9 on the second equation

3x - 6y = -15

3(2y - 9) - 6y = -15

3(2y) + 3(-9) - 6y = -15

6y - 27 - 6y = -15

-27 = -15

Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.

5 0

1 year ago

Did I do my math homework right?

anastassius [24]

Yes you did it correctly but change problem 5’s denominator on the right to a 6

7 0

3 years ago