We need to solve for x. Let's try problem b:
![2x-6=3x+1-x-7](https://tex.z-dn.net/?f=2x-6%3D3x%2B1-x-7)
Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:
![2x-6=2x-6](https://tex.z-dn.net/?f=2x-6%3D2x-6)
Since this is true, your answer would be:
All real numbers
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Let's solve for problem c:
![3x+1=43](https://tex.z-dn.net/?f=3x%2B1%3D43)
Let's isolate x, so subtract 1 from both sides:
![3x=42](https://tex.z-dn.net/?f=3x%3D42)
Since x can't have a coefficient, divide both sides by 3:
![\frac{3x}{3}=\frac{42}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D%5Cfrac%7B42%7D%7B3%7D)
![x=14](https://tex.z-dn.net/?f=x%3D14)
So, only the value of 14 would make this equation true.
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Let's try problem d:
![4x-1=4x+7](https://tex.z-dn.net/?f=4x-1%3D4x%2B7)
Let's get our whole numbers on the right side. Add 1 to both sides:
![4x=4x+8](https://tex.z-dn.net/?f=4x%3D4x%2B8)
Subtract 4x from the right side on both sides:
![0=8](https://tex.z-dn.net/?f=0%3D8)
Since this is not true, your answer would be:
No solution
Answer: 5 63/100
Since the numerator is greater than the denominator, we got an IMPROPER fraction. So we can also express it as a MIXED NUMBER, although we know that 563/100 is also equal to 5 63/100 when written as a mixed number.
3x - 2y = 13
-2y = -3x + 13
y = 3/2x - 13/2...slope is 3/2, y int is -13/2
2x + 3y = -16
3y = -2x - 16
y = -2/3x - 16/3...slope = -2/3, y int is -16/3
perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, flip the number and change the sign.
On the 1st equation, the slope was 3/2....find its negative reciprocal.....flip it, making it 2/3....change the sign...making it -2/3. So the negative reciprocal of 3/2 is -2/3.
So if one equation has a slope of 3/2 and another equation has a slope of -2/3, then these lines are perpendicular <==
Answer:
A. 5x = 45
Step-by-step explanation:
To check, substitute 9 for x in each equation.
A. 5*9 = 45
B. 2*9 ≠ 20
C. 4 + 9 ≠ 12
D. 9 +7 ≠ 26
Answer:
Step-by-step explanation:
Givens
a = 2
r = 4
n = 10
tn = ??
Formula
tn = ar^(n - 1)
Solution
t_10 = 2 * 4^(10 - 1)
t_10 = 2 * 4^9
t_10 = 524288