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Vilka [71]
3 years ago
9

In a marathon 90% runner were managed to complete it and 30% were men if 270 men completed it how many total runner began the ma

rathon
Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

1000 runners

Step-by-step explanation:

Take total number of runners to be -----------x

90% of x managed to complete the marathon= 90/100 × x =0.9x

30% of those who completed the marathon were men= 30% × 0.9x

=0.3×0.9x= 0.27x

=270 men completed the marathon; this means

0.27x=270--------------------------------find x by dividing both sides by 0.27

x= 270/0.27

x=1000 runners

KatRina [158]3 years ago
6 0

Answer:

1000

Step-by-step explanation:

Given : In a marathon 90% runner were managed to complete it and 30% were men.

To Find: If 270 men completed it how many total runner began the marathon.

Solution:

Let x be the number of total runners

Now we are given that 90% runner were managed to complete it

So, number of runners managed to complete = 90\% \times x =\frac{90}{100}x=0.9x

Now we are given that out of 90% , 30% were men

So, Numbers of men runners = 30\% \times 0.9x=\frac{30}{100} \times 0.9x =0.27x

Now we are given that 270 men completed it

So, 0.27x=270

x=\frac{270}{0.27}

[tex]x=1000/tex]

Hence 1000 runners began the marathon.

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Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show
Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is P(x \ge 60)=0.0901

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

        in every 1000 children a particular genetic defect occurs to 1

        The number of sample selected is n= 50,000

The probability of observing the defect is mathematically evaluated as

              p = \frac{1}{1000}

                 = 0.001

The probability of not observing the defect is mathematically evaluated as

            q = 1-p

               = 1-0.001

               = 0.999

The mean of this probability is mathematically represented as

                 \mu = np

Substituting values

                \mu = 50000*0.001

                    = 50

The standard deviation of this probability is mathematically represented as

   \sigma = \sqrt{npq}

Substituting values

      = \sqrt{50000 * 0.001 * 0.999}

     = \sqrt{49.95}

     = 7.07

 the probability of detecting  x  \ge60 defects can be represented in as  normal distribution like

       P(x \ge 60)

in standardizing the normal distribution the normal area used to approximate P(x \ge 60) is the right of 59.5 instead of 60 because  x= 60 is part of the observation

The z -score is obtained mathematically as

                z = \frac{x-\mu }{\sigma }

                   = \frac{59.5 - 50 }{7.07}

                  =1.34

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

  The total area under the curve is 1

So

    P(x \ge 60) \approx P(z > 1.34)

                     = 1-P(z \le 1.34)

                    =1-0.9099

                  =0.0901

             

   

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