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Vilka [71]
3 years ago
9

In a marathon 90% runner were managed to complete it and 30% were men if 270 men completed it how many total runner began the ma

rathon
Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

1000 runners

Step-by-step explanation:

Take total number of runners to be -----------x

90% of x managed to complete the marathon= 90/100 × x =0.9x

30% of those who completed the marathon were men= 30% × 0.9x

=0.3×0.9x= 0.27x

=270 men completed the marathon; this means

0.27x=270--------------------------------find x by dividing both sides by 0.27

x= 270/0.27

x=1000 runners

KatRina [158]3 years ago
6 0

Answer:

1000

Step-by-step explanation:

Given : In a marathon 90% runner were managed to complete it and 30% were men.

To Find: If 270 men completed it how many total runner began the marathon.

Solution:

Let x be the number of total runners

Now we are given that 90% runner were managed to complete it

So, number of runners managed to complete = 90\% \times x =\frac{90}{100}x=0.9x

Now we are given that out of 90% , 30% were men

So, Numbers of men runners = 30\% \times 0.9x=\frac{30}{100} \times 0.9x =0.27x

Now we are given that 270 men completed it

So, 0.27x=270

x=\frac{270}{0.27}

[tex]x=1000/tex]

Hence 1000 runners began the marathon.

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Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50
VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

\texttt{ }

<em>Jaces songs were played on 6 more commercials than movies.</em>

\boxed{C = 6 + M} → <em>Equation 1</em>

\texttt{ }

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

\boxed{50C + 140M = 680} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1  ↔ Equation 2 :</em>

50C + 140M = 680

50 ( 6 + M ) + 140M = 680

300 + 50M + 140M = 680

190M = 680 - 300

190M = 380

M = 380 \div 190

M = 2

\texttt{ }

C = 6 + M

C = 6 + 2

C = 8

\texttt{ }

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

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