1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vilka [71]
3 years ago
9

In a marathon 90% runner were managed to complete it and 30% were men if 270 men completed it how many total runner began the ma

rathon
Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

1000 runners

Step-by-step explanation:

Take total number of runners to be -----------x

90% of x managed to complete the marathon= 90/100 × x =0.9x

30% of those who completed the marathon were men= 30% × 0.9x

=0.3×0.9x= 0.27x

=270 men completed the marathon; this means

0.27x=270--------------------------------find x by dividing both sides by 0.27

x= 270/0.27

x=1000 runners

KatRina [158]3 years ago
6 0

Answer:

1000

Step-by-step explanation:

Given : In a marathon 90% runner were managed to complete it and 30% were men.

To Find: If 270 men completed it how many total runner began the marathon.

Solution:

Let x be the number of total runners

Now we are given that 90% runner were managed to complete it

So, number of runners managed to complete = 90\% \times x =\frac{90}{100}x=0.9x

Now we are given that out of 90% , 30% were men

So, Numbers of men runners = 30\% \times 0.9x=\frac{30}{100} \times 0.9x =0.27x

Now we are given that 270 men completed it

So, 0.27x=270

x=\frac{270}{0.27}

[tex]x=1000/tex]

Hence 1000 runners began the marathon.

You might be interested in
Find the value of y...​
soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

33^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1

Calculate:

(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1

Solve using substitution:

(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1     t=3^{y}

Solve the equation for t:

t^{2}*\frac{1}{3}+\frac{2}{3}t=1

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

3^{y}=1

y=0

5 0
2 years ago
Find the area of the composite figure.
Tamiku [17]
Area =leagth x wigth
4 0
3 years ago
Read 2 more answers
Please help me with this problem​
Nookie1986 [14]
In order for two lines to be perpendicular, their slopes must multiply together to equal to negative one
So we do negative one divided by 2/5 to get the slope of the red line
Which is -5/2
To check, we do 2/5 multiplied by -5/2 which equals to -1 so our answer is correct
8 0
3 years ago
Read 2 more answers
a can of pinapple juice is a cylinder with a radius of 2.4 in. and a height of 11. what is the are odf the label around the can
pshichka [43]
A=2πrh+2πr²
A≈202.07
hopes that helps


8 0
2 years ago
Which is the outlier in this set of values?<br> 17 20 19 10 15 19 14 0 11 16
Musya8 [376]

Answer:

Zero is the outlier.

Step-by-step explanation:

the rest of the numbers are all two-digit numbers while zero is one digit and farther away on a number line.

hope i helped!

8 0
3 years ago
Other questions:
  • How do you do -9(x+5-9)=9--9
    14·1 answer
  • Which problem is best modeled by the expression. 7 ÷ 1/4?
    5·1 answer
  • Is This Answer Correct (A)
    12·1 answer
  • A line has____rotational symmetry,
    15·2 answers
  • Need help double checking answers for proof writing geometry!
    9·1 answer
  • Only answer if you know the real answer please appreciate it answer question number 2 please
    7·1 answer
  • Please only right answers no links or anything and please answer quick!!!ILL MARK BRAINLEST PLEASE QUICK QUICK QUICK QUICK QUICK
    14·1 answer
  • John was building a wall out of bricks the weight of the wall was 543.75
    14·2 answers
  • The InSight robotic lander traveled from Earth to Mars. The distance between the planets is approximately 3×108 miles and the ro
    9·1 answer
  • Triangle 2 is a scale drawing of Triangle 1. Based on information in the diagram, what is the length of side b?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!