Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
This means for every 5 students there will be 1 teacher so 550/5=110
So answer is 110 teachers
Answer:
The first number lets say is x
the second is y so
y=1/2x+8
x+1/2x+8=58
1 1/2x=50
x= 33 1/3
Hope This Helps!!!
<span>❅b. compound
Compound is a substance that is made of atoms of more then on type bound together. </span><span />
Assuming you have some angle measures, you could use the
Law of Sines to solve for the missing side lengths, which states that,

,
where a, b, and c correspond to the given sides you have, and A, B, and C represent the angles you have.
In this scenario, you would have to have the values for c (which we do), and have the angle measure of C. In addition, we would also need an angle measure that is either A or B.
Hope this helps a bit!
:)