The perimeter of a parallelgram is the sum of the lengths of its four sides.
Parallelogram ABCD has sides AB, BC, CD, and AB.
Sides AB and CD are parallel and of equal length = 19 units.
Sides BC and CD are parallel and of equal length. Assuming thi is the length of 5 units given in the statement, the perimeter of the parallelogram ABCD is: 19 units + 19 units + 5 units + 5 units = 48 units.
Please, inform if the length of 5 units corresponds to other distance, but even in that case, with this explanation you should be able to calculate the perimeter of this and other parallelograms.
Answer: 48 untis.
Answer:
(5,-8)
Step-by-step explanation:
if it is reflected across the X axis and this is in quadrant 3 that means if it was reflected it would fall in quadrant 2
We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
where
(h,k)-----> is the center
r--------> is the radius
is the center is the point (0,0) and radius r=20
then
(h,k) is (0,0)
(x-0)²+(y-0)²=20²---------> (x)²+(y)²=400
the answer is
the option D.) x2 + y2 = 400
Answer:
The answer is 11,374
Step-by-step explanation:
First we find 5% of 9,400 is.
9,400 * 5% = 470
Next we add 9,400 with 470 then multiply by 20%
9,400 + 470 = 9,870
9,870 * 20% = 1974
Next we add.
9,870 + 1,974 = 11,374
So, the answer is 11,374
Hope this helps! :)
