Step-by-step explanation:
1. (2+4+1)/9 = 7/9
2. 2 1/3 + 2/3 = 2 + (1+2)/3 = 2 + 3/3 = 2+1 = 3
3. 1 1/5 + 2 3/5 = 1+2 + 1/5 + 3/5 = 3 + (1+3)/5 =
3 4/5
4. 5/6 + 2/10 + 1/5 = 5/6 + 1/5 + 1/5 = 5/6 + 2/5
= (5×5)/(6×5) + (2×6)/(5×6)
= 25/30 + 12/30
= (25+12)/30
= 37/30 = 1 7/30
5. 3 1/2 + 4 2/3
= 3+4 + 1/2 + 2/3
= 7 + (1×3)/(2×3) + (2×2)/(3×2)
= 7 + 3/6 + 4/6
= 7 + (3+4)/6 = 7 7/6 = 8 1/6
6. 9/13 - 5/13 = (9-5)/13 = 4/13
7. 7 6/8 - 5 2/8
= (7-5) + (6/8 - 2/8)
= 2 + 4/8
= 2 1/2
8. 2/3 - 3/7
= (2×7)/(3×7) - (3×3)/(7×3)
= 14/21 - 9/21 = (14-9)/21 = 5/21
9. 11 1/5 - 5 4/5
= 10 6/5 - 5 4/5
= (10-5) + (6/5 - 4/5)
= 5 + 2/5 = 5 2/5
10. 15 4/5 - 7 7/10
= (15-7) + (4/5 - 7/10)
= 8 + (4×2)/(5×2) - 7/10
= 8 + 8/10 - 7/10
= 8 + 1/10
= 8 1/10
Answer:
a)= 2
b) 6.324
c) P= 0.1217
Step-by-step explanation:
a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)
b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by
σ_X`1- X`2 = √σ²/n1 +σ²/n2
Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2
so
σ_X`1- X`2 =√20 +20 = 6.324
if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.
Where as Z is normally distributed with mean zero and unit variance.
If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then
Z= 0-2/ 6.342= -0.31625
P(-0.31625<z<0)= 0.1217
The probability would be 0.1217
Answer:
I think it might be 1 17/18
(not sure)
Step-by-step explanation:
what I did was break down 3 1/2 and I got 2 3/2 I then Subtracted that by 1 5/9 (I don't know if it's right sorry if I'm wrong)
Answer:
There is a formula for this:
[Worker 1 Time * Worker 2 Time] / [Worker 1 Time + Worker 2 Time]
[2 * 1.5] / [2 + 1.5] = 3.0 / 3.5
= 0.8571428571 Hours =
51.43 minutes
Both Jenna and Juan are INCORRECT.
Step-by-step explanation:
Answer:
{3, 4, 5, 6, 7, 8, 9, 10, 11}
Step-by-step explanation:
Let integer be x
x > 2 and x < 12
gives
2 < x < 12
All such integers are {3, 4, 5, 6, 7, 8, 9, 10, 11}
