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netineya [11]
3 years ago
5

Please help me ASAP!!

Mathematics
2 answers:
pshichka [43]3 years ago
6 0

Answer: Supergirl = 19 and Wonder Woman = 8

<u>Step-by-step explanation:</u>

Let g represent the quantity of Supergirl keychains and w represent the quantity of Wonder Woman keychains.

                             <u>Qty</u>       <u>Cost</u>

Supergirl                 g         $3g

<u>Wonder Woman</u>  <u>   w    </u>   <u> $2w</u>

Total                       27       $73

Qty:     g +  w  = 27  →   -2(g +  w  = 27)    →    -2g - 2w = -54

Cost: 3g + 2w = 73  →     1(3g + 2w = 73)  →    <u> 3g + 2w</u> =<u>  73 </u>

                                                                            g          =  19

Input g = 19 into one of the original equations to solve for w:

 g  + w = 27

(19) + w = 27

         w = 8

marshall27 [118]3 years ago
3 0
She bought 19 supergirl and 8 Wonder Woman keychains. Good luck on the homework

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Need help with what the answer to this question is
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The answer is C
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5 0
3 years ago
Jill has a photograph that is 4 inches wide by 6 inches high. If she enlarges it so that the width is 12
Nadya [2.5K]

Answer:

The inches in height will be 18 inches.

Step-by-step explanation:

Okay so we know that the original width is 4 inches and she enlarged that to 12 inches

So what we first have to do is find out how much did the photograph "grow" per se. To find this we have to divide 12 by 4. 12 divided by 4 = 3.

So, the width of the photograph grew "times 3" inches

Now whatever you do to the width you have to do to the height. In this case, what is "3 times" 6 (which is the height). 3 times 6 = 18 inches

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The inches in height will be 18 inches.

Jill has a square with a width of 12 inches, and a height of 18 inches.

Have a wonderful day!

5 0
3 years ago
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klasskru [66]

Answer:

t = 3.673900

Step-by-step explanation:

Given

df = 28 -- degree of freedom

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Required

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The given parameters can be illustrated as follows:

P(T > t) = \alpha

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\alpha = 0.005

So, we have:

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To solve further, we make use of the attached the student's t distribution table.

From the attached table,

The t-value is given at the row with df = 28 and \alpha = 0.005 is 3.673900

Hence, t = 3.673900

4 0
2 years ago
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