Answer:

Step-by-step explanation:



I think is D
5^-2*25^-1
5^-2*5^-2
5^-4
1/5^4
1/625
0,0016, 5^-4
There are 210 different possible combinations
<h3>How to determine the number of possible combinations?</h3>
The given parameters are:
- Types of candy, n = 10
- Candies to taste, r = 6
The number of possible combinations is calculated using:
Combination = nCr
This gives
Combination = 10C6
Apply the combination formula
Combination = (10!)/((10 - 6)!6!)
Evaluate
Combination = 210
Hence, there are 210 different possible combinations
Read more about combination at:
brainly.com/question/11732255
Answer:
she can have 4 marbles in the bag.
Step-by-step explanation:
Because if one out of four is read then there is four marbles.
1)solve for y.
4x+y=7
Add -4x to both sides.
4x+y+−4x=7+−4x
y=−4x+7
2) solve for y.
y−5x=9
Add 5x to both sides.
−5x+y+5x=9+5x
y=5x+9
3) solve for y.
3y−15x=12
Add 15x to both sides.
−15x+3y+15x=12+15x
3y=15x+12
Divide both sides by 3.
3y/3=15x+12/3
y=5x+4
4) solve for y.
8x+2y=18
Add -8x to both sides.
8x+2y+−8x=18+−8x
2y=−8x+18
Divide both sides by 2.
2y/2=−8x+18/2
y=−4x+9
5 ) solve for y.
7x−y=35
Add -7x to both sides.
7x−y+−7x=35+−7x
−y=−7x+35
Divide both sides by -1.
−y/−1=−7x+35/−1
y=7x−35
6) solve for y.
4x+1=9+4y
Flip the equation.
4y+9=4x+1
Add -9 to both sides.
4y+9+−9=4x+1+−9
4y=4x−8
Divide both sides by 4.
4y/4=4x−8/4
y=x−2
7) solve for x.
y=5x−2x
Flip the equation.
3x=y
Divide both sides by 3.
3x/3=y/3
x=1/3y
8) solve for x.
r=x+9x
Flip the equation.
10x=r
Divide both sides by 10.
10x/10=r/10
x=1/10r
9) solve for x.
b=3x+9xy
Flip the equation.
9xy+3x=b
Factor out variable x.
x(9y+3)=b
Divide both sides by 9y+3.
x(9y+3)/9y+3=b/9y+3
x=b/9y+3
10) solve for x.
w=2hx−11x
Flip the equation.
2hx−11x=w
Factor out variable x.
x(2h−11)=w
Divide both sides by 2h-11.
x(2h−11)/2h−11 = w/2h−11
x=w/2h−11
11) solve for x.
p=4x+qx−5
Flip the equation.
qx+4x−5=p
Add 5 to both sides.
qx+4x−5+5=p+5
qx+4x=p+5
Factor out variable x.
x(q+4)=p+5
Divide both sides by q+4.
x(q+4)/q+4=p+5/q+4
x=p+5 / q+4
12) solve for x.
m=9+3x−dx
Flip the equation.
−dx+3x+9=m
Add -9 to both sides.
−dx+3x+9+−9=m+−9
−dx+3x=m−9
Factor out variable x.
x(−d+3)=m−9
Divide both sides by -d+3.
x(−d+3)/−d+3=m−9/−d+3
x=m−9/−d+3