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zavuch27 [327]
3 years ago
9

Calcium carbonate () is 34.5% Ca by mass. In a 418 g sample of , how many grams of calcium are present?

Chemistry
1 answer:
erastovalidia [21]3 years ago
8 0

Answer:

144.2 g of Ca are present in 418 g of sample

Explanation:

34.5 % Ca → In 100 g of salt there are 34.5 g of Ca

Let's make a rule of three:

In 100 g of salt there are 34.5 g of Ca

In 418 g of salt there must be (418 . 34.5) / 100 = 144.2 g

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I need help please ASAP
nalin [4]

Answer:

A

Explanation:

because CO2 is carbon dioxide and CO is carbon monoxide. mono meaning one which in this case is monoxide.

6 0
3 years ago
What is the pH of a solution with a concentration of 4.7 × 10-4 molar H3O+?
wlad13 [49]
The pH of a liquid substance is calculated through the equation,
                                       pH = -log[H3O+]
Substituting the given concentration of the hydronium ion to the equation above,
                                        pH = -log[4.7x10^-4 M]
The value of pH is equal to 3.33. Thus, the pH of the solution is approximately 3.33. 
3 0
3 years ago
The main factor which effects the speed of a sound wave is the ____
Radda [10]

Answer:

it depends on the medium and the temperature

Explanation:

3 0
3 years ago
What is a substance that cannot be broken down further by chemical means
IgorC [24]
Anything can be broken down, as long as it is not as small as an atom
8 0
3 years ago
In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?
Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

8 0
3 years ago
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