2 years ago

Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.

1 answer:

4 0

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=0 $2b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4$

Step-by-step explanation:

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ahrayia [7]

What do you mean by solve?
Put in slope-intercept form would be: y<(3/4)x+1

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Maslowich

$\frac{3}{6}^{/3}= \frac{1}{2}$

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Inessa05 [86]

Answer:

(x+4)(x+4)

Step-by-step explanation:

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Serga [27]

I think B would be the right answer

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Fittoniya [83]

3/2=1 & 1/2
5/10 = 1/2
1&1/1/2 = 2

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