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vova2212 [387]
3 years ago
8

Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=02b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4

Step-by-step explanation:

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Find 3 consecutive even integers if their sum decreased by 10 equals -22
Orlov [11]
Three consecutive even integers can be represented by x, (x+2), and (x+4).

(x + (x + 2) + (x + 4)) - 10 = -22   Get rid of the parentheses
    x + x + 2 + x + 4 - 10 = -22   Combine like terms (x + x + x) and (2 + 4 - 10)
                               3x - 4 = -22   Add 4 to both sides
                                    3x = -18   Divide
                                      x = -6
Check you work.

x = -6
x + 2 = -4
x + 4 = -2

(-6 - 4 - 2) - 10 = 22
-12 - 10 = -22

So, your three integers are -6, -4, and -2 .
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Answer:

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Step-by-step explanation:

2×10=20

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Explique melhor, se eu entender consigo te ajuda :)
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