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vova2212 [387]
3 years ago
8

Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=02b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4

Step-by-step explanation:

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Calculate the circumference and area of this circle. 4cm radius​
Alja [10]

Answer:

the circumference is 25.133 and the area is 50.265

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2 years ago
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Amira bought 3.34 lbs. of grapes at $0.67 per pound. How much money did she spend?
Andreas93 [3]

Answer:

$2.24

Step-by-step explanation:

you multiply 3.34 and 0.67 then you round

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3 years ago
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(18)-(4-2)x 2<br><br> Plz help
Verdich [7]

Answer:

so first u do (4-2) which is 2

then minus 18 from 2 which is 16

then u multiply by 2 which is 32

therefore the answer is 32

5 0
3 years ago
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What are the roots of the equation 9x^2 + 54x +82 = 0 in simplest a + bi form?​
s344n2d4d5 [400]

Answer:

The roots are

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Step-by-step explanation:

9x² + 54x + 82 = 0

Using the quadratic formula

That's

<h3>x =  \frac{ - b\pm \sqrt{ {b}^{2}  - 4ac} }{2a}</h3>

From the question

a = 9 , b = 54 , c = 82

Substitute the values into the above formula and solve

That's

<h3>x =  \frac{ - 54\pm \sqrt{ {54}^{2}  - 4(9)(82)} }{2(9)}  \\ x =  \frac{ - 54\pm \sqrt{2916 - 2952} }{18}  \\ x =  \frac{ - 54\pm \sqrt{ - 36} }{18}  \\ x =  \frac{ - 54\pm 6i}{18}</h3>

Separate the real and imaginary parts

That's

<h3>x =  -  \frac{54}{18} \pm \frac{6}{18}  \: i \\ x =  - 3\pm \frac{1}{3} i</h3>

We have the final answer as

<h3>x =  - 3 +  \frac{1}{3}  i \:  \:  \: or \:  \:  \: x =  - 3 -  \frac{1}{3} i \\</h3>

Hope this helps you

5 0
3 years ago
VODU
garri49 [273]

Answer:

r = ∛(3V/4π)

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr³.

We want to solve this first for r³ and then for r.

Multiplying both sides of V = (4/3)πr³ by 3 yields an equation without fractions:  3V = 4πr³.

Dividing both sides of this equation by 4π isolates r³:

       3V

r³ = -------

       4π

To find r, take the cube root of both sides of

       3V

r³ = -------

       4π

obtaining r = ∛(3V/4π)

3 0
3 years ago
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